Support and protect the body is NOT a function of the digestive system
Your body's skeletal structure serves as a support system. It gives the body its structure, permits mobility, produces blood cells, offers organs protection, and stores minerals. A different name for the skeletal system is the musculoskeletal system.
<h3>What is digestive system ?</h3>
The digestive system consists of organs that are crucial for breaking down both food and water. These include the anus, pharynx (throat), stomach, small and large intestines, rectum, and oesophagus.
- The body needs nutrients for energy, growth, and cell repair, and nutrients are broken down into via the digestive process. Prior to the blood absorbing nutrients from food and drink and transporting them to body cells, those nutrients must be broken down into smaller molecules.
Learn more about Digestive system here:
brainly.com/question/21470803
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Answer:
Part a)
![a_t = 0.423 m/s^2](https://tex.z-dn.net/?f=a_t%20%3D%200.423%20m%2Fs%5E2)
Part b)
![a_c = 2113 m/s^2](https://tex.z-dn.net/?f=a_c%20%3D%202113%20m%2Fs%5E2)
Part c)
![d = 80 m](https://tex.z-dn.net/?f=d%20%3D%2080%20m)
Explanation:
Part a)
as we know that angular acceleration of the wheel is given as
![\alpha = 13.2 rad/s^2](https://tex.z-dn.net/?f=%5Calpha%20%3D%2013.2%20rad%2Fs%5E2)
now the radius of the wheel is given as
R = 3.21 cm
so the tangential acceleration is given as
![a_t = R\alpha](https://tex.z-dn.net/?f=a_t%20%3D%20R%5Calpha)
![a_t = (0.0321)(13.2)](https://tex.z-dn.net/?f=a_t%20%3D%20%280.0321%29%2813.2%29)
![a_t = 0.423 m/s^2](https://tex.z-dn.net/?f=a_t%20%3D%200.423%20m%2Fs%5E2)
Part b)
frequency of the wheel at maximum speed is given as
![f = 2450 rev/min](https://tex.z-dn.net/?f=f%20%3D%202450%20rev%2Fmin)
![f = \frac{2450}{60} = 40.8 rev/s](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7B2450%7D%7B60%7D%20%3D%2040.8%20rev%2Fs)
now we know that
![\omega = 2\pi f = 2\pi(40.8) = 256.56 rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D%202%5Cpi%20f%20%3D%202%5Cpi%2840.8%29%20%3D%20256.56%20rad%2Fs)
now radial acceleration is given as
![a_c = \omega^2 r](https://tex.z-dn.net/?f=a_c%20%3D%20%5Comega%5E2%20r)
![a_c = (256.56)^2(0.0321) = 2113 m/s^2](https://tex.z-dn.net/?f=a_c%20%3D%20%28256.56%29%5E2%280.0321%29%20%3D%202113%20m%2Fs%5E2)
Part c)
total angular displacement of the point on rim is given as
![\Delta \theta = \omega_0 t + \frac{1}{2}\alpha t^2](https://tex.z-dn.net/?f=%5CDelta%20%5Ctheta%20%3D%20%5Comega_0%20t%20%2B%20%5Cfrac%7B1%7D%7B2%7D%5Calpha%20t%5E2)
here we know that
![\omega = \omega_0 + \alpha t](https://tex.z-dn.net/?f=%5Comega%20%3D%20%5Comega_0%20%2B%20%5Calpha%20t)
![256.56 = 0 + 13.2 t](https://tex.z-dn.net/?f=256.56%20%3D%200%20%2B%2013.2%20t)
![t = 19.4 s](https://tex.z-dn.net/?f=t%20%3D%2019.4%20s)
now angular displacement will be
![\Delta \theta = 0 + \frac{1}{2}(13.2)(19.4)^2](https://tex.z-dn.net/?f=%5CDelta%20%5Ctheta%20%3D%200%20%2B%20%5Cfrac%7B1%7D%7B2%7D%2813.2%29%2819.4%29%5E2)
![\Delta \theta = 2493.3 rad](https://tex.z-dn.net/?f=%5CDelta%20%5Ctheta%20%3D%202493.3%20rad)
now the distance moved by the point on the rim is given as
![d = R\theta](https://tex.z-dn.net/?f=d%20%3D%20R%5Ctheta)
![d = (0.0321)(2493.3)](https://tex.z-dn.net/?f=d%20%3D%20%280.0321%29%282493.3%29)
![d = 80 m](https://tex.z-dn.net/?f=d%20%3D%2080%20m)
The answer is:
1.8 meters.
Explanation:
An athlete swinging can be considered a pendulum.
The pendulum's maximum height is the point at which it changes direction, which means that its velocity is equal to zero. In this point, for the mechanical energy conservation, all its kinetic energy is transformed into potential energy. Similarly, when the pendulum is at its resting position (when the athlete grabs the rope), its energy is totally kinetic.
Therefore we can say that:
![\frac{1}{2}m v_{1} ^{2} = mgh_{max}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7Dm%20v_%7B1%7D%20%5E%7B2%7D%20%20%3D%20mgh_%7Bmax%7D%20)
Solving for h:
![h_{max} = \frac{v^{2}}{g}](https://tex.z-dn.net/?f=h_%7Bmax%7D%20%3D%20%20%5Cfrac%7Bv%5E%7B2%7D%7D%7Bg%7D%20)
As we can see, the maximum height is independent on the mass and on the length of the rope, therefore it will be the same for the 100kg-athlete as it is for the 50kg-athlete, since their initial speeds are the same.
We know that the <span>50kg-athlete reached a height of 1.8 m, h</span>ence, the maximum height reached by the 100kg-athlete will be
1.8 m.