Answer;
the colors of light that plants require for photosynthesis
Explanation;
The color of light used for photosynthesis depends on the pigment in the plant. For example, green plants with chlorophylls and carotenoids have a maximum activity with violet-blue and red light.
White light contains various colors, including red, orange, yellow, green, blue, indigo and violet. When plants harvest light for photosynthesis, they only absorb a few colors and reflect the rest. Plants appear green because chlorophyll absorbs other colors and reflects green.
Answer:
M = 6.32 x 10⁻⁶ H
Explanation:
given,
Length of solenoid = 10 cm = 0.1 m
diameter = 0.40 cm
radius = 0.2 cm = 0.002
number of turns, N₁ = 800
N₂ = 50
mutual inductance will be equal to


M = 6.32 x 10⁻⁶ H
hence, mutual inductance of the combination of two coil is equal to M = 6.32 x 10⁻⁶ H
Explanation:
Given that,
Radius of the circular loop, r = 3.5 cm = 0.035 m
(a) During a 0.12-s time interval, the magnitude of the field increases uniformly from 0.2 T to 0.5 T. Due to the change in the magnetic field, an emf will induced in it. The magnitude of induced emf is given by :

So, the magnitude of the emf induced in the loop during the time interval is
.
(b) The negative sign shows that the direction of induced emf in the loop is in anitclockwise direction.
The given question is incomplete. The complete question is as follows.
The block has a weight of 75 lb and rests on the floor for which
= 0.4. The motor draws in the cable at a constant rate of 6 ft/sft/s. Neglect the mass of the cable and pulleys.
Determine the output of the motor at the instant
.
Explanation:
We will consider that equilibrium condition in vertical direction is as follows.

N - W = 0
N = W
or, N = 75 lb
Again, equilibrium condition in the vertical direction is as follows.

= 0

= 
= 30 lb
Now, the equilibrium equation in the horizontal direction is as follows.



or, T = 
= 
= 
= 17.32 lb
Now, we will calculate the output power of the motor as follows.
P = Tv
= 
= 
= 0.189 hp
or, = 0.2 hp
Thus, we can conclude that output of the given motor is 0.2 hp.