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blsea [12.9K]
3 years ago
15

If the resistance of a circuit is 3 ohms, and the voltage produced by the cell in the

Physics
1 answer:
skad [1K]3 years ago
5 0

Answer:

The magnitude of the current is 4A (amperes).

Explanation:

We can use V=IR, where V stands for Voltage, I stands for current, and R stands for resistance to solve this problem.

A such:

V=12\\I=\text{ ?}\\R=3\\\\\text{Solve for I}:\\12=3I\\3I=12\\I=\frac{12}{3}\\I=4\text{A}

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There is little sunlight at high latitudes during the winter, so few crops can grow even if temperatures are regulated. To addre
Kruka [31]

Answer;

the colors of light that plants require for photosynthesis

Explanation;

The color of light used for photosynthesis depends on the pigment in the plant. For example, green plants with chlorophylls and carotenoids have a maximum activity with violet-blue and red light.

White light contains various colors, including red, orange, yellow, green, blue, indigo and violet. When plants harvest light for photosynthesis, they only absorb a few colors and reflect the rest. Plants appear green because chlorophyll absorbs other colors and reflects green.

7 0
3 years ago
Read 2 more answers
A 10.0-cm-long solenoid of diameter 0.400 cm is wound uniformly with 800 turns. A second coil with 50 turns is wound around the
levacccp [35]

Answer:

M = 6.32 x 10⁻⁶ H

Explanation:

given,

Length of solenoid = 10 cm = 0.1 m

diameter = 0.40 cm

radius = 0.2 cm = 0.002

number of turns, N₁ = 800

                            N₂ = 50

mutual inductance will be equal to  

     M = \dfrac{\mu_0N_1N_2A}{l}

     M = \dfrac{4\pi \times 10^{-7}\times 800\times 50 \times \pi \times (0.002)^2}{0.01}

           M = 6.32 x 10⁻⁶ H

hence, mutual inductance of the combination of two coil is equal to  M = 6.32 x 10⁻⁶ H

7 0
4 years ago
A single-turn circular loop of wire that has a radius of 3.5 cm lies in the plane perpendicular to a spatially uniform magnetic
Lena [83]

Explanation:

Given that,

Radius of the circular loop, r = 3.5 cm = 0.035 m

(a) During a 0.12-s time interval, the magnitude of the field increases uniformly from 0.2 T to 0.5 T. Due to the change in the magnetic field, an emf will induced in it. The magnitude of induced emf is given by :

\epsilon=-\dfrac{d(BA)}{dt}\\\\\epsilon=-\pi r^2\dfrac{B_f-B_i}{dt}\\\\\epsilon=-\pi (0.035)^2\dfrac{0.5-0.2}{0.12}\\\\\epsilon=-9.62\times 10^{-3}\ volts

So, the magnitude of the emf induced in the loop during the time interval is 9.62\times 10^{-3}\ V.

(b) The negative sign shows that the direction of induced emf in the loop is in anitclockwise direction.

5 0
3 years ago
A light bulb converts electrical energy into into which of the following?
Shalnov [3]
Heat and light energy
3 0
3 years ago
Read 2 more answers
The block has a weight of 75 lblb and rests on the floor for which μkμk = 0.4. The motor draws in the cable at a constant rate o
WINSTONCH [101]

The given question is incomplete. The complete question is as follows.

The block has a weight of 75 lb and rests on the floor for which \mu k = 0.4. The motor draws in the cable at a constant rate of 6 ft/sft/s. Neglect the mass of the cable and pulleys.

Determine the output of the motor at the instant \theta = 30^{o}.

Explanation:

We will consider that equilibrium condition in vertical direction is as follows.

           \sum F_{y} = 0

         N - W = 0

           N = W

or,      N = 75 lb

Again, equilibrium condition in the vertical direction is  as follows.

        \sum F_{x} = 0

       T_{2} - F_{k} = 0

         T_{2} = \mu_{k} N

                  = 0.4 \times 75 lb

                  = 30 lb

Now, the equilibrium equation in the horizontal direction is as follows.

         \sum F_{x} = 0

       T Cos (30^{o}) + T Cos (30^{o}) = T_{2}

          2T Cos (30^{o}) = T_{2}

    or,             T = \frac{T_{2}}{2 Cos (30^{o})}

                        = \frac{30}{2 Cos (30^{o})}

                        = \frac{30}{1.732}

                        = 17.32 lb

Now, we will calculate the output power of the motor as follows.

             P = Tv

                = 17.32 lb \times 6

                = 103.92 \times \frac{1}{550} \times \frac{hp}{ft/s}

                = 0.189 hp

or,             = 0.2 hp

Thus, we can conclude that output of the given motor is 0.2 hp.

3 0
3 years ago
Read 2 more answers
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