Answer:
Part a)
Velocity = 6.9 m/s
Part b)
Position = (3.6 m, 5.175 m)
Explanation:
Initial position of the particle is ORIGIN
also it initial speed is along +X direction given as
now the acceleration is given as
when particle reaches to its maximum x coordinate then its velocity in x direction will become zero
so we will have
Part a)
the velocity of the particle at this moment in Y direction is given as
Part b)
X coordinate of the particle at this time
Y coordinate of the particle at this time
so position is given as (3.6 m, 5.175 m)
D) because the refrigerator was much heavier than the other objects
The answer is c to take a pictures with the camera in the metal hall
Answer:
y₁ = 37.2 m, y₂ = 22,6 m
Explanation:
For this exercise we can use the kinematic equations
For the globe, with index 1
y₁ = y₀ + v₁ t
For the shot with index 2
y₂ = 0 + v₂ t - ½ g t²
At the point where the position of the two bodies meet is the same
y₁ = y₂
y₀ + v₁ t = v₂ t - ½ g t²
14 + 8.40t = 27.0 t - ½ 9.8 t²
4.9 t² - 18.6 t + 14 = 0
t² - 3,796 t + 2,857 = 0
Let's look for time by solving the second degree equation
t = [3,796 ±√(3,796 2 - 4 2,857)] / 2
t = [3,796 ± 1,727] / 2
t₁ = 2.7615 s
t₂ = 1.03 s
Now we can calculate the distance for each time
y₁ = v₂ t₁ - ½ g t₁²
y₁ = 27 2.7615 - ½ 9.8 2.7615²
y₁ = 37.2 m
y₂ = v₂ t₂ - ½ g t₂²
y₂ = 27 1.03 - ½ 9.8 1.03²
y₂ = 22,612 m
