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steposvetlana [31]
3 years ago
13

Objects 1 and 2 attract each other with a gravitational force

Physics
1 answer:
snow_tiger [21]3 years ago
7 0

Answer:

F' = 162 units

Explanation:

The gravitational force of attraction between the two objects is given by Newton's Gravitational law through the following formula:

F = \frac{Gm_{1}m_{2}}{r^{2}}\\\\

where,

F = gravitational force = 18 units

G = Gravitational Constant

m₁ = mass of object 1

m₂ = mass of object 2

r = distance between objects

Therefore,

18 = \frac{Gm_{1}m_{2}}{r^{2}}------ eqn (1)\\\\

Now, if we change the value of distance to one-third of original value, then:

r' = r/3

F' = \frac{Gm_{1}m_{2}}{(\frac{r}{3})^{2}}\\\\F' = (9)(\frac{Gm_{1}m_{2}}{r^{2}})

using eqn (1):

F' = 9(18 units)

<u>F' = 162 units</u>

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Explanation:

Formula for calculating the area of a  rectangle A = Length *width

For statement A;

Given area of a rectangle with measured length = 2.536 mm and width = 1.4 mm.

Area of the rectangle = 2.536mm * 1.4mm

Area of the rectangle = 3.5504mm²

The rule of significant figures states that we should always convert the answer to the least number of significant figure amount the given value in question. Since 1.4mm has 2 significant figure, hence we will convert our answer to 2 significant figure.

Area of the rectangle = 3.6mm² (to 2sf)

For statement B;

Given area of a rectangle with measured length = 2.536 mm and width = 1.41 mm.

Area of the rectangle = 2.536mm * 1.41mm

Area of the rectangle = 3.57576mm²

Similarly, Since 1.41mm has 3 significant figure compare to 2.536 that has 4sf, hence we will convert our answer to 3 significant figure.

Area of the rectangle = 3.58mm² (to 3sf)

Based on the conversion, it can be seen that 3.6mm²  is greater than 3.58mm², hence the area of rectangle in statement A is greater than the area of the rectangle in statement B.

7 0
3 years ago
Please help on this one?
kupik [55]

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Two difference between lever and pulley​
Annette [7]

Answer:

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I hope this helps you

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3 years ago
An object weighs 42.53 newtons. What is its mass if a gravitometer indicates that g = 9.83 m/s2? Round to the nearest tenth.
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4 years ago
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Rudik [331]
The re<span>sistance of the second wire is 16 R.
where R is the resistance of the first wire.

R = </span>ρ\frac{l}{A}
where l = length of the wire
A = area of the wire
A = \pi r^{2} where, r = \frac{diameter of wire}{2}

Thus, on finding the ratio of resistance of the two wires, we get,

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