Explanation:
Formula for calculating the area of a rectangle A = Length *width
For statement A;
Given area of a rectangle with measured length = 2.536 mm and width = 1.4 mm.
Area of the rectangle = 2.536mm * 1.4mm
Area of the rectangle = 3.5504mm²
The rule of significant figures states that we should always convert the answer to the least number of significant figure amount the given value in question. Since 1.4mm has 2 significant figure, hence we will convert our answer to 2 significant figure.
Area of the rectangle = 3.6mm² (to 2sf)
For statement B;
Given area of a rectangle with measured length = 2.536 mm and width = 1.41 mm.
Area of the rectangle = 2.536mm * 1.41mm
Area of the rectangle = 3.57576mm²
Similarly, Since 1.41mm has 3 significant figure compare to 2.536 that has 4sf, hence we will convert our answer to 3 significant figure.
Area of the rectangle = 3.58mm² (to 3sf)
Based on the conversion, it can be seen that 3.6mm² is greater than 3.58mm², hence the area of rectangle in statement A is greater than the area of the rectangle in statement B.
Answer: A)30V. First find the current of the circuit. I=V/R(total resistance). So I=60/120=0.5. Now to find voltage drop in R3 use ohms law as given. V(of 3)=(0.5)(60)=30V
Answer:
Differences can be :
1. Lever is onr of the six simple machines but pulley is a simple machine which has a wheel and axle .
2. Lever is of 3 types (first class , second class , third class ) but pulley is of only 2 types
I hope this helps you
The re<span>sistance of the second wire is 16 R.
where R is the resistance of the first wire.
R = </span>ρ

where l = length of the wire
A = area of the wire
A =

where, r =

Thus, on finding the ratio of resistance of the two wires, we get,

here, R1 = R
l1 = 8m
l2 = 2m
A1=π

A1=π

we get. R2 = 16R