Mass connects: Matter and Energy.
Explanation:
Hope this answer helps.
The empirical formula is C₂H₆O.
We must calculate the <em>masses of C, H, and O</em> from the masses given.
<em>Mass of C</em> =38.20 g CO₂ × (12.01 g C/44.01 g CO₂) = 10.424 g C
<em>Mass of H</em> = 23.48 g H₂O × (2.016 g H/18.02 g H₂O) = 2.6268 g H
<em>Mass of O</em> = Mass of compound - Mass of C - Mass of H
= (20.00 – 10.424 – 2.6268) g = 6.9487 g
Now, we must <em>convert these masses to moles</em> and <em>find their ratios</em>.
From here on, I like to summarize the calculations in a table.
<u>Element</u> <u>Mass/g</u> <u>Moles</u> <u>Ratio</u> <u>Integers</u>
C 10.424 0.8680 1.999 2
H 2.6268 2.606 6.001 6
O 6.9487 0.4343 1 1
The empirical formula is C₂H₆O.
Answer:What is your question?
Explanation:
It is exothermic. Exothermic reaction is a reaction that gives out heat and energy. Sodium is a highly reactive metal that is found in group 1 in the periodic table. We all know that all group 1 elements(alkali metals) are usually stored in inert liquid like oil to prevent contact with air and water so as to prevent an explosion. An explosion is a form of a exothermic reaction since it gives out heat and light. Hence, the reaction between Na and water is an exothermic reaction.
Have a nice day ahead.
Answer : The concentration of and at equilibrium is, 0.0031 M and 0.0741 M respectively.
Explanation : Given,
Moles of = 0.166 mol
Volume of solution = 2.15 L
First we have to calculate the concentration of
Now we have to calculate the concentration of and at equilibrium.
Initial conc. 0.0772 0 0
At eqm. 0.0772-x x x
The expression for equilibrium constant is:
By solving the term, we get the value of 'x'.
x = 0.0741
Thus,
The concentration of at equilibrium = (0.0772-x) = (0.0772-0.0741) = 0.0031 M
The concentration of at equilibrium = x = 0.0741 M