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vovangra [49]
3 years ago
15

Help please i beg someone answer and explain

Chemistry
1 answer:
Novosadov [1.4K]3 years ago
3 0

Answer:

Q,N,1) lithium + hydrochloric -> lithium chloride + Hydrogen.

  1. word equation ( 2li + 2HCl -> 2liCl + H2)
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Calculate the pH of a solution prepared by dissolving 0.15 mol benzoic acid (C7H5O2H) and 0.30 mol of sodium benzoate (Na C7H5O2
asambeis [7]

Answer : The pH of a solution is, 4.5

Explanation : Given,

Moles of benzoic acid = 0.15 mol

Moles of sodium benzoate = 0.30 mol

Volume of solution = 1.00 L

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First we have to calculate the value of pK_a.

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (6.5\times 10^{-5})

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Now we have to calculate the pH of a solution.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

Now put all the given values in this expression, we get:

pH=4.2+\log [\frac{(\frac{0.30}{1.00L})}{(\frac{0.15}{1.00L})}]

pH=4.5

Therefore, the pH of a solution is, 4.5

8 0
4 years ago
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