I believe
the answer is C. 0.14cm.
The zero error in vernier caliper is read by the distance by which the zero of the movable part of the scale is shifted from the zero of the cm ruler in the tool, which is the unmovable part of the tool. The movable part has a scale accuracy of 0.1 cm, while the other has a scale accuracy of 1 cm. And we always use the lowest scale, which is here the 0.1 scale which has greater accuracy with 10 times the 1 cm ruler, to find our errors.
Hope this helps!
Velocity can change when there is a change in direction and speed.
The correct answer is: Option (3) 9.8 N/kg
Explanation:
According to Newton's Law of Gravitation:
--- (1)
Where G = Gravitational constant = 6.67408 × 10⁻¹¹ m³ kg⁻¹ s⁻²
m = Mass of the body = 2 kg
M = Mass of the Earth = 5.972 × 10²⁴ kg
R = Distance of the object from the center of the Earth = Radius of the Earth + Object's distance from the surface of the Earth = (6371 * 10³) + 3.0 = 6371003 m
Plug in the values in (1):
(1)=>
Now that we have force strength at the location, we can use:
Force = mass * gravitational-field-strength
Plug in the values:
19.63 = 2.0 * gravitational-field-strength
gravitational-field-strength = 19.63/2 = 9.82 N/kg
Hence the correct answer is Option (3) 9.8 N/kg
Explanation:
initial velocity 0, final velocity 8.00,time taken 2×60= 120+50=170,now using formula a=v_u\t=8.00-0/170=8.00/170=