Answer:
Explanation:
Fe⁺²(aq) + ClO₂(aq) → Fe⁺³(aq) + ClO₂⁻(aq)
Here oxidation number of Fe is increased from +2 to +3 , so Fe is oxidised .
The oxidation number of Cl is reduced from + 4 to +3 so Cl is reduced .
So ClO₂(aq) is oxidising agent and Fe⁺²(aq) is reducing agent .
There are two N≡N bonds and three H–H bonds are in reactants.
Given:
The reaction between nitrogen gas and hydrogen gas.
To find:
Bonds on the reactant side
Solution:
Reactants in the reaction = 
The bond between nitrogen atoms in single 
molecule = N≡N (triple bond)
Then in two molecules = 2 N≡N (triple bonds)
The bond between hydrogen atoms in single 
molecule = H-H (single bond)
Then in three molecules = 3 H-H (single bonds)
Product in the reaction =
The bonds between nitrogen and hydrogen atoms in single molecule = 3 N-H (single bond)
Then in two molecules = 6 N-H (single bonds)
So, there are two N≡N bonds and three H–H bonds are in reactants.
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Two sublevels of the same principal energy level differ from each other through shape and size.
There are mainly 4 energy level s, p, d and f.
The s level has one orbital and one orbital have two electrons. So the maximum number of electron in s sublevel is 2.
The p level has three orbital and one orbital have two electrons. So the maximum number of electron in s sublevel is 6.
The d level has five orbital and one orbital have two electrons. So the maximum number of electron in s sublevel is 10.
The f level has 7 orbital and one orbital have two electrons. So the maximum number of electron in s sublevel is 14.
They may be differ in magnetic level.
Thus, we concluded that Two sublevels of the same principal energy level differ from each other through shape and size.
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The molality of a solute is equal to the moles of solute per kg of solvent. We are given the mole fraction of I₂ in CH₂Cl₂ is <em>X</em> = 0.115. If we can an arbitrary sample of 1 mole of solution, we will have:
0.115 mol I₂
1 - 0.115 = 0.885 mol CH₂Cl₂
We need moles of solute, which we have, and must convert our moles of solvent to kg:
0.885 mol x 84.93 g/mol = 75.2 g CH₂Cl₂ x 1 kg/1000g = 0.0752 kg CH₂Cl₂
We can now calculate the molality:
m = 0.115 mol I₂/0.0752 kg CH₂Cl₂
m = 1.53 mol I₂/kg CH₂Cl₂
The molality of the iodine solution is 1.53.
The oxidation number sulfur in H₂S is -2.
A compound's total number of oxidations must be zero.
The two hydrogen atoms in the chemical hydrogen sulfide, H₂S, each have an oxidation number of +1, making a total of +2. As a result, the compound's sulfur has an oxidation number of -2, and the total number of oxidations is 0.
Assume that the sulfur atom in H₂S has an oxidation number of x.
S be x.
Now,
2+x=0
⇒x=−2
<h3>What is oxidation number?</h3>
The total number of electrons that an atom either receives or loses in order to create a chemical connection with another atom is known as the oxidation number, also known as the oxidation state.
Depending on whether we are taking into account the electronegativity of the atoms or not, these phrases can occasionally have a distinct meaning. Coordination chemistry commonly makes use of the phrase "oxidation number."
<h3>What distinguishes an oxidation number from an oxidation state?</h3>
In contrast to the oxidation state, which indicates how oxidised an atom is in a molecule, the oxidation number describes the charge that the core metal atom will retain once all ligands have been removed.
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