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algol [13]
3 years ago
11

The net ionic equation for the reaction between aqueous nitric acid and aqueous sodium hydroxide is ________. h+ (aq) + na+ (aq)

+ oh- (aq) → h2o (l) + na+ (aq) h+ (aq) + hno3 (aq) + 2oh- (aq) → 2h2o (l) + no3- (aq) h+ (aq) + oh- (aq) → h2o (l) hno3 (aq) + naoh (aq) → nano3 (aq) + h2o (l) hno3 (aq) + oh- (aq) → no3- (aq) + h2o (l)
Chemistry
1 answer:
Nana76 [90]3 years ago
7 0
HNO3+NaOH ----> H2O
H⁺ +NO3⁻+Na⁺+OH⁻ ---> Na⁺ +NO3⁻ +H2O
H⁺ (aq)+OH⁻(aq)----> H2O(l)
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A change in velocity can occur without a change in speed *<br> A: True<br><br> B: False?
Mrrafil [7]

Answer: True

Explanation: For example, changing direction can change velocity

6 0
2 years ago
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If the mass of an object is 60.0 grams and the density of the object is 15.0 g/mL, what is the volume of the object? The formula
laila [671]

Answer:

168.56 mL

Explanation:

density = mass/volume, use basic algebra skills to replace the volume and solve

7 0
2 years ago
What is the molar mass of Al2(SO4)3​
umka21 [38]

Answer:

The molar mass of Al_2(SO_4)_3​ is 342.145 g/mol

Explanation:

The molar mass  is stated as the “mass per unit amount of substance”of a given chemical compound  

Al_2(SO_4)_3​  is Aluminium sulphate. They easily dissolve in water. It is primarily  used as a 'coagulating agent' in the drinking water purification and also in waste and sewage water treatment plants,  

We know,

Atomic weight of Aluminium =  26.981

Atomic weight of Sulphur= 32.065

Atomic weight of  Oxygen =  15.9994

Now molar mass of  Al_2(SO_4)_3​ (Aluminium sulphate) is

=>2(26.981)+3(32.065+4(15.999))

=>53.962 +3(32.065+63.996)

=>53.962+3(96.061)

=>53.962+288.183

=>342.145

4 0
3 years ago
If it takes 38.70cm of 1.90M NaOH to neutralize 10.30cm of H2SO4 in a battery, what is the molarity of H2SO4?
slamgirl [31]

Answer:

The molarity of the acid, H₂SO₄ is 3.57 M

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

H₂SO₄ + 2NaOH —> Na₂SO₄ + 2H₂O

From the balanced equation above,

Mole ratio of the acid, H₂SO₄ (nₐ) = 1

Mole ratio of the base, NaOH (n₆) = 2

Finally, we shall determine the molarity of the acid, H₂SO₄. This can be obtained as follow:

Volume of base, NaOH (V₆) = 38.70 cm³

Molarity of base, NaOH (M₆) = 1.90M

Volume of acid, H₂SO₄ (Vₐ) = 10.30 cm³

Molarity of acid, H₂SO₄ (Mₐ) =?

MₐVₐ / M₆V₆ = nₐ/n₆

Mₐ × 10.3 / 1.9 × 38.70 = 1/2

Mₐ × 10.3 / 73.53 = 1/2

Cross multiply

Mₐ × 10.3 × 2 = 73.53 × 1

Mₐ × 20.6 = 73.53

Divide both side by 20.6

Mₐ = 73.53 / 20.6

Mₐ = 3.57 M

Thus, the molarity of the acid, H₂SO₄ is 3.57 M

8 0
2 years ago
Please help me (40 points)
Maksim231197 [3]

Answer:

P=15

N=16

Explanation:

4 0
2 years ago
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