Answer: 40.68 kPa
Explanation:
Given that,
Original volume of gas V1 = 21.7 mL
Original pressure of gas P1 = 98.8 kPa
New volume of gas V2 = 52.7 mL
New pressure of gas P2 = ?
Since pressure and volume are given while temperature is constant, apply the formula for Boyle's law
P1V1 = P2V2
98.8 kPa x 21.7 mL = P2 x 52.7L
2143.96 kPa L = 52.7 L x P2
P2 = 2143.96 kPa L / 52.7 L
P2 = 40.68 kPa
Thus, the new pressure of the gas is 40.68 kPa.
The sample of argon gas that has the same number of atoms as a 100 milliliter sample of helium gas at 1.0 atm and 300 is 100. mL at 1.0 atm and 300. K
The correct option is D.
<h3>What is the number of moles of gases in the given samples?</h3>
The number of moles of gases in each of the given samples of gas is found below using the ideal gas equation.
The ideal gas equation is: PV/RT = n
where;
- P is pressure
- V is volume
- n is number of moles of gas
- T is temperature of gas
- R is molar gas constant = 0.082 atm.L/mol/K
Moles of gas in the given helium gas sample:
P = 1.0 atm, V = 100 mL or 0.1 L, T = 300 K
n = 1 * 0.1 / 0.082 * 300
n = 0.00406 moles
For the argon gas sample:
A. n = 1 * 0.05 / 0.082 * 300
n = 0.00203 moles
B. n = 0.5 * 0.05 / 0.082 * 300
n = 0.00102 moles
C. n = 0.5 * 0.1 / 0.082 * 300
n = 0.00203 moles
D. n = 1 * 0.1 / 0.082 * 300
n = 0.00406 moles
Learn more about ideal gas equation at: brainly.com/question/24236411
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Sorry for the scribbles lol
Answer:
Molar mass = (24.31 + 2 × 35.45) = 95.21 g mol–1 i.e. 95.21 g of MgCl2 is exactly 1 mole.
Explanation:
Answer:
it is soluble in water
Explanation:
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