Answer:
W= 8120 KJ
Explanation:
Given that
Process is isothermal ,it means that temperature of the gas will remain constant.
T₁=T₂ = 400 K
The change in the entropy given ΔS = 20.3 KJ/K
Lets take heat transfer is Q ,then entropy change can be written as
Now by putting the values
Q= 20.3 x 400 KJ
Q= 8120 KJ
The heat transfer ,Q= 8120 KJ
From first law of thermodynamics
Q = ΔU + W
ΔU =Change in the internal energy ,W=Work
Q=Heat transfer
For ideal gas ΔU = m Cv ΔT]
At constant temperature process ,ΔT= 0
That is why ΔU = 0
Q = ΔU + W
Q = 0+ W
Q=W= 8120 KJ
Work ,W= 8120 KJ
Answer:
Benefits that last a lifetime. The Army offers you money for education, comprehensive health care, generous vacation time, family services and support groups, special pay and cash allowances to cover the cost of living.
Answer:
i would say C but i may be wrong have a great day
Explanation:
Answer:
M_o = 18.84 N*m in the clockwise direction.
Explanation:
Given:
- Force F = 120 N
- base b = 610 mm
- height h = 330 mm
Find:
Moment M_o about origin and its direction:
Solution:
- The force has two components F_x and F_y along base b and height h, respectively:
F_x = F*cos(Q)
F_x = F*(h / sqrt (h^2 + b^2))
F_x = 120*(330 / sqrt (330^2 + 610^2))
F_x = 57.098 N
- We can skip F_y as it passes through the the origin, hence moment produced is zero.
- Moment about O is :
M_o = F_x * h
M_o = 57.098*.33
M_o = 18.84 N*m in the clockwise direction.
