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2 years ago

Will a simple circuit work without a switch? Explain why or why not.

1 answer:

7 0

yes, a simple circuit will work without a switch. If we don't have a switch in a circuit then whichever device you are using electricity for wouldn't be able to switch off and will be working continuously. An open/close switch is usually all that is needed to supply or disconnect power from the source to the circuit.So, the circuit will work but it will work continuously.

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A 20 kg mass is thrown from the ground to a height of 50 m. (a) find the kinetic energy of the mass at this height. (b) find the

horrorfan [7]

Answer:

(a) 0 kJ

(b) 9.81 kJ

Explanation:

(a)

From the law of conservation of energy, energy can only be transformed from one state to another. At a height of 50 m, all the kinetic energy is converted to potential energy hence KE=0

(b)

Potential energy, PE=mgh where m is the mass, g is acceleration due to gravity and h is the height

Substituting 50 m for h and 20 Kg for m, taking g as 9.81 then

PE=20*9.81*50=9810 J=9.81 kJ

(c)

Relating the equation of potential energy to the equation of kinetic energy, which is $0.5mv^{2}$

$mgh=0.5mv^{2}$ where v is the velocity of the mass

$v=\sqrt {2gh}$

Substituting 50 m for h and taking g as 9.81 then

$v=\sqrt {2*9.81*50}=31.32091953\approx 31.32 m/s$

3 0

2 years ago

The convection coefficient for flow over a solid sphere may be determined by submerging the sphere, which is initially at 25 °C,

sashaice [31]

Answer:

t = 59.37 s

Explanation:

Given data:

thermal diffusivity $= \alpha = \frac{k}{\rho c_p} =0.40\times 10^{-0.5}$

theraml conductivity = k = 22 W/m.K

h = 300 W/ m^2.K

$T_i$ = 25 degree C = 298 k

$T_o$ = 60 degree C = 333 k

$T_{\infty}$ = 75 degree C = 348 L

diameter d = 0.1 m

characteristics length Lc = r/3 = = 0.0166

$Bi = \frac{hLc}{K} = \frac{300\times 0.0166}{22} = 0.226$

$\tau = \frac{\alpha t}{lc^2} = \frac{0.4\times 10^{-5}\times t}{0.0166^2}$

$\tau = 0.036 t$

$\frac{T_o -T_{\infty}}{T_i -T_{\infty}} = Ae^[\lambda^2 \tau}$

at Bi = 0.226

Ai = 0.982

$\lambda = 0.876$

$\frac{333348}{298-348} = 0.982e^{-0.879^2 0.036t}$

$0.3 = 0.982 e^{-0.2t}$

$0.305 = e^{-0.2t}$

-1.187 = - 0.02t

t = 59.37 s

7 0

2 years ago

Andy has applied for a NICET

r-ruslan [8.4K]

Yes she did that’s the answers

4 0

2 years ago

Air enters the combustor of a jet engine at Pressure=10 atm, T=1000R and M=0.2. Fuel is injected and burned with fuel-air ratio

kkurt [141]

Air enters the combustor of a jet engine at p1 = 10 atm, T1 = 1000 °R and M1 = 0.2. The
heat released during combustion is 4.5x108 ft-lb per slug of fuel. Assuming onedimensional
frictionless flow with γ = 1.4 for the fuel air mixture, calculate M2, p2, T2 at
the exit of the combustor. Hope this helps! Can I get brainly please? Plus safety first if you see any links don’t klick them please don’t.

5 0

3 years ago

One way to lower NOx emissions in diesel engines is to add water to the fuel. Since water is not mixable with diesel fuel, it ha

Colt1911 [192]

After the emulsion is made, fuel droplet containing water droplets increase its temperature inside the engine, because of that, water droplets explode causing water rapid evaporation that break down fuel droplet, in consequence, smaller fuel droplets are generated. This makes the temperature of the flame during the combustion decrease, and that is why the reduction of NOx is accomplished by this method .

6 0

3 years ago