The tension in the cord is 14.7 N and the force of pull of the cord is 14.7 N, assuming the block is stationary.
<h3>
What is the tension in the cord?</h3>
The tension in the cord is calculated as follows;
T = ma + mg
where;
- a is the acceleration of the block
- g is acceleration due to gravity
- m is mass of the block
T = m(a + g)
T = 1.5(a + 9.8)
T = 1.5a + 14.7
Thus, the tension in the cord is (1.5a + 14.7) N.
If the block is at rest, the tension is 14.7 N.
<h3>Force of the force</h3>
The force with which the cord pulls is equal to the tension in the cord
F = T = m(a + g)
F = (1.5a + 14.7) N
If the block is stationary, a = 0, the tension and force of pull of the cord = 14.7 N.
Thus, the tension in the cord is 14.7 N and the force of pull of the cord is 14.7 N, assuming the block is stationary.
Learn more about tension here: brainly.com/question/187404
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An object<span> with twice as much mass will exert twice as much </span>gravitational<span> pull on other </span>objects<span>. The </span>gravitational<span> force increases as the size of an </span>object<span>increases. On the other hand, the strength of </span>gravity<span> is inversely </span>related<span> to the square of the distance between two </span>objects<span>.</span>
A) Vt = Vo - gt
= 0 - 9.8 . 2
= - 19.6 m/sec (acting downward)
b) ∆y = Vt^2 - Vo^2 / 2g
= (-19.6)^2 - 0 / 19.6 = 19.6 meters
To solve this problem, apply the concepts related to the centripetal acceleration as the equivalent of gravity, and the kinematic equations of linear motion that will relate the speed, the distance traveled and the period of the body to meet the needs given in the problem. Centripetal acceleration is defined as,

Here,
v = Tangential Velocity
r = Radius
If we rearrange the equation to get the velocity we have,

But at this case the centripetal acceleration must be equal to the gravitational at the Earth, then



The perimeter of the cylinder would be given by,



Therefore now related by kinematic equations of linear motion the speed with the distance traveled and the time we will have to




Therefore the period will be 44.9s