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KonstantinChe [14]
3 years ago
4

The position of an object at any time t is given by s(t)=3t4−40t3+126t2−9. i. Determine the velocity of the object at any time t

. [5 marks] ii.Does the object ever stop changing? [5 marks] iii.When is the object moving to the right and when is the object moving to the left?
Physics
1 answer:
kozerog [31]3 years ago
0 0

Answer:

1.) V = 12t^3 - 120t^2 + 252t

2.) No

3.) At positive V and negative V

Explanation: Given that the position of an object at any time t is s(t)=3t4−40t3+126t2−9.

1.) To determine the velocity V, we will differenciate the equation above with respect to t.

V = ds/dt

ds/dt = 12t^3 - 120t^2 + 252t

Therefore,

V = 12t^3 - 120t^2 + 252t

2.) The equation above depict an exponential equation which proves that the object never stops changing.

3.) The object moves to the right at positive velocity V and moves to the left at negative velocity V

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Answer/solution:

Given :

Mass =5kg

T 1 =20 C,T 2  =100 ∘C

ΔT=100−20=80 ∘C

Q=m×C×ΔT

where C= specific heat capacity of water

=4200J/(kgK)

Q=5×4200×80

=1680000 Joule.

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2 years ago
One car travels 56 meters due east in 2.0 seconds, and a second car travels 84 meters due west in 3.0 seconds. During their peri
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Answer:

  average speed

Explanation:

The directions were different, so the velocities could not be the same.

However, the magnitude of the velocity (speed) was 56/2 = 28 m/s for the first car, and 84/3 = 28 m/s for the second car. These<em> average speeds are the same</em>.

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3 years ago
Which statement about an element’s average atomic mass is correct? a. It is determined by counting the number of isotopes in a s
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Answer choice C is the best answer
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3 years ago
hergy A Sprinter runs at a a forward velocity of 10,9 m/s. If the sprinter has a mass of 72.5 kg, What is the Sprinter's Kinetic
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Answer:

4306.8625 J or 344549/80J (fraction form)

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7 0
1 year ago
Express the angular velocity ω of the wheel in terms of the displacement d, the magnitude F of the applied force, and the moment
zhuklara [117]

Answer:

The angular velocity of the wheel in terms of d, F, and I is,  ω = d/t (F/I α)    s⁻¹

Explanation:

Given,

The angular velocity ω

The displacement d

The magnitude of the applied force, F

The moment of inertia of the wheel I = mr²

The angular velocity can be written as

                         ω = v /r

where,

                     v - linear velocity

                      r - radius of the wheel

                          ω = d/t (1/r)               (∵ v = d /t)

The force can be written as,

                          F = m a

                              = m α r                  (∵ a = α r)

Multiplying both sides by r

                          F r = m r² α

                           F r = I α                     (∵ I = mr²)

                              r = I α / F

Substituting in the above equation for ω

                          ω = d/t (F/I α)    s⁻¹

Hence, the angular velocity of the wheel in terms of d, F, and I is,  ω = d/t (F/I α)    s⁻¹

8 0
3 years ago
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