Answer:
41.02m
Explanation:
Given parameters:
Initial velocity = 0m/s
Final velocity = 96km/hr
Time taken = 3.07s
Unknown:
Distance traveled by the time the final speed was achieved = ?
Solution:
To solve this problem, we first find the acceleration of the car;
Acceleration =
v is the final velocity
u is the initial velocity
t is the time taken
Now convert the the final velocity to m/s;
96km/hr to m/s;
1 km/hr = 0.278m/s
96km/hr = 96 x 0.278 = 26.7m/s
Now;
Acceleration =
= 8.69m/s²
So;
v² = u² + 2as
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance
26.7² = 0² + 2 x 8.69 x s
712.89 = 17.38s
s = 41.02m
1) The acceleration of the plane is 1.89 times the acceleration of gravity
2) The force acting on the airplane is 
Explanation:
1)
The acceleration of the plane is given by

where
v is the final velocity of the plane
u is the initial velocity
t is the time elapsed
For the airplane in this problem, we have:
(it starts from rest)
is the final velocity
is the time
Substituting, we find

The acceleration of gravity is

So, the acceleration of the plane relative to
is

2)
The average force exerted on the plane is given by Newton's second law:

where
F is the force
m is the mass of the airplane
a is the acceleration
In this problem, we have
is the mass of the plane
is the acceleration
Substituting, we find:

Learn more about acceleration and forces:
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Answer:
Explanation:
Hooke's law is represented by thee formula
F = ke where F is force in N and K is the spring constant.
Initial length of the spring = 34cm = 0.34 m
mass of 7.00kg hung
weight = mg = 7 × 9.8 = 68.6 N
Final length of the spring = 44.5 cm = 0.445 m
extension = final length - initial length = 0.445 m - 0.34 m = 0.105 m
a) F = Ke
K = F / e = 68.6 N /0.105 m = 653.33 N/m = 0.653 kN/m
b) F = 150 N
k = 653.33 N/m
F = ke
150 N / 653.33 N/m = e
e = 0.23 m
new length = 0.34 + 0.23= 0.57 m = 57 cm
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