Answer/solution:
Given :
Mass =5kg
T 1 =20 C,T 2 =100 ∘C
ΔT=100−20=80 ∘C
Q=m×C×ΔT
where C= specific heat capacity of water
=4200J/(kgK)
Q=5×4200×80
=1680000 Joule.
=1680KJ
Answer:
average speed
Explanation:
The directions were different, so the velocities could not be the same.
However, the magnitude of the velocity (speed) was 56/2 = 28 m/s for the first car, and 84/3 = 28 m/s for the second car. These<em> average speeds are the same</em>.
Answer:
4306.8625 J or 344549/80J (fraction form)
Explanation:
kinetic energy=
mv²
=
×72.5×10.9²
= 4306.8625 J or 344549/80 J
Answer:
The angular velocity of the wheel in terms of d, F, and I is, ω = d/t (F/I α) s⁻¹
Explanation:
Given,
The angular velocity ω
The displacement d
The magnitude of the applied force, F
The moment of inertia of the wheel I = mr²
The angular velocity can be written as
ω = v /r
where,
v - linear velocity
r - radius of the wheel
ω = d/t (1/r) (∵ v = d /t)
The force can be written as,
F = m a
= m α r (∵ a = α r)
Multiplying both sides by r
F r = m r² α
F r = I α (∵ I = mr²)
r = I α / F
Substituting in the above equation for ω
ω = d/t (F/I α) s⁻¹
Hence, the angular velocity of the wheel in terms of d, F, and I is, ω = d/t (F/I α) s⁻¹