Answer:
1.) V = 12t^3 - 120t^2 + 252t
2.) No
3.) At positive V and negative V
Explanation: Given that the position of an object at any time t is s(t)=3t4−40t3+126t2−9.
1.) To determine the velocity V, we will differenciate the equation above with respect to t.
V = ds/dt
ds/dt = 12t^3 - 120t^2 + 252t
Therefore,
V = 12t^3 - 120t^2 + 252t
2.) The equation above depict an exponential equation which proves that the object never stops changing.
3.) The object moves to the right at positive velocity V and moves to the left at negative velocity V
