Need a lot of help plz
1 answer:
You might be interested in
1) The distance travelled by the electron is
2) The time taken is
Explanation:
1)
The electron in this problem is moving by uniformly accelerated motion (constant acceleration), so we can use the following suvat equation
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance travelled
For the electron in this problem,
is the initial velocity
v = 0 is the final velocity (it comes to a stop)
is the acceleration
Solving for s, we find the distance travelled:
2)
The total time taken for the electron in its motion can also be found by using another suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time taken
Here we have
v = 0
And solving for t, we find the time taken:
Learn more about accelerated motion:
#LearnwithBrainly
Answer:
t= 27.38 mins [this the time taken by the enzyme to hydrolyse 80% of the fat present]
Explanation:given values
Half life of lipase t_1/2 = 8 min x 60s/min = 480 s
Rate constant for first order reaction
k_d = 0.6932/480 = 1.44 x 10^-3 s-1
Initial fat concentration S_0 = 45 mol/m3 = 45 mmol/L
rate of hydrolysis Vm0 = 0.07 mmol/L/s
Conversion X = 0.80
Final concentration S = S_0(1-X) = 45 (1-0.80) = 9 mol/m3
K_m = 5mmol/L
time take is given by
all values are given and putting these value we get
t=1642.83 secs
which is equal to
t= 27.38 mins [this the time taken by the enzyme to hydrolyse 80% of the fat present]