Answer:
Explanation:
Given
Ship A velocity is 40 mph and is traveling 35 west of north
Therefore in 2 hours it will travel 
thus its position vector after two hours is

similarly B travels with 20 mph and in 2 hours
![=20\times 2=40 miles Its position vector[tex]r_B=40sin80\hat{i}+40cos80\hat{j}](https://tex.z-dn.net/?f=%3D20%5Ctimes%202%3D40%20miles%20%3C%2Fp%3E%3Cp%3EIts%20position%20vector%5Btex%5Dr_B%3D40sin80%5Chat%7Bi%7D%2B40cos80%5Chat%7Bj%7D)
Thus distance between A and B is



Velocity of A

Velocity of B

Velocity of A w.r.t B


Kinetic Energy = 1/2 * m * v²
1/2 * 30 * 20²
1/2 * 30 * 400
12000/2
6000 J.
It is in the noble gas group which has a full valence electron shell found in group 18
Answer:
n = 756.25 giga electrons
Explanation:
It is given that,
If the charge on the negative plate of the capacitor, 
Let n is the number of excess electrons are on that plate. Using the quantization of charges, the total charge on the negative plate is given by :

e is the charge on electron

or
n = 756.25 giga electrons
So, there are 756.25 giga electrons are on the plate. Hence, this is the required solution.