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irakobra [83]
3 years ago
13

if the percent yield ofr the following reaction is 75% and 45.0g of NO2 are consumed with ercess water in the reaction. how many

grams of nitric acid HNO3(aq) are produced.
Chemistry
1 answer:
NISA [10]3 years ago
6 0

Answer:

30.8 grams of nitric acid are produced

Explanation:

Let's state the reaction:

3 NO₂ + H₂O → 2 HNO₃ + NO

If water is the excess reagent, then the limiting is the gas.

We convert the mass to moles:

45 g . 1 mol/ 46 g = 0.978 moles

Ratio is 3:2. 3 moles of gas can produce 2 moles of acid

Then, 0.978 moles may produce (0.978 . 2) /3 = 0.652 moles of acid

This is the 100% yield, but in this case, the percent yield is 75%

0.652 moles . 0.75 = 0.489 moles

Let's convert the moles to mass → 0.489 mol . 63g / 1mol = 30.8 g

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Svetradugi [14.3K]
This is true i think if that is a question
4 0
3 years ago
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The yttrium- nuclide radioactively decays by electron capture. Write a balanced nuclear chemical equation that describes this pr
evablogger [386]

Answer:

See explanation and image attached

Explanation:

Yttrium has many isotopes, the lowest mass number of Yttrium  is 89Y.

Recall that electron capture converts an electron into a proton and then into a neutron with a consequent emission of a neutrino (v).

In electron capture, the mass number of the daughter nucleus remains the same as that of the parent nucleus while the atomic number of the daughter nucleus is less than that of the parent by one unit.

8 0
3 years ago
Determine the specific heat ofmaterial if a 12g sample absorbed 48j as it was heated from 20-40
devlian [24]

Answer:

c =0.2 J/g.°C

Explanation:

Given data:

Specific heat of material = ?

Mass of sample = 12 g

Heat absorbed = 48 J

Initial temperature = 20°C

Final temperature = 40°C

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =  40°C -20°C

ΔT =  20°C

48 J = 12 g×c×20°C

48 J =240 g.°C×c

c = 48 J/240 g.°C

c =0.2 J/g.°C

6 0
3 years ago
The radioactivity of U-235 is of low intensity. Why then were the people of Hiroshima exposed to high intensity radiation in the
Marina86 [1]

Answer:

Explanation:

What occurred then is as a result of nuclear fission. This occurs as the Uranium-235 split into two smaller nuclei while releasing high energy neutrons. These neutrons bombard existing U-235 in the atmosphere and this reaction continue in a spontaneous manner until a chain reaction is formed of U-235, whose fall out fills the environment. This process was what led to people been exposed to high intensity radiation in the days and months after the atomic bomb was dropped.

7 0
3 years ago
The temperature of a sample of water changes from 10°C to 20°C when the water absorbs 100 calories of heat. What is the mass of
Vlad1618 [11]

Answer:

10 g

Explanation:

Right from the start, just by inspecting the values given, you can say that the answer will be  

10 g

.

Now, here's what that is the case.

As you know, a substance's specific heat tells you how much heat is needed to increase the temperature of  

1 g

of that substance by  

1

∘

C

.

Water has a specific heat of approximately  

4.18

J

g

∘

C

. This tells you that in order to increase the temperature of  

1 g

of water by  

1

∘

C

, you need to provide  

4.18 J

of heat.

Now, how much heat would be required to increase the temperature of  

1 g

of water by  

10

∘

C

?

Well, you'd need  

4.18 J

to increase it by  

1

∘

C

, another  

4.18 J

to increase it by another  

1

∘

C

, and so on. This means that you'd need

4.18 J

×

10

=

41.8 J

to increase the temperature of  

1 g

of water by  

10

∘

C

.

Now look at the value given to you. If you need  

41.8 J

to increase the temperature of  

1 g

of water by  

10

∘

C

, what mass of water would require  

10

times as much heat to increase its temperature by  

10

∘

C

?

1 g

×

10

=

10 g

And that's your answer.

Mathematically, you can calculate this by using the equation

q

=

m

⋅

c

⋅

Δ

T

 

, where

q

- heat absorbed/lost

m

- the mass of the sample

c

- the specific heat of the substance

Δ

T

- the change in temperature, defined as final temperature minus initial temperature

Plug in your values to get

418

J

=

m

⋅

4.18

J

g

∘

C

⋅

(

20

−

10

)

∘

C

m

=

418

4.18

⋅

10

=

10 g

5 0
3 years ago
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