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malfutka [58]
3 years ago
6

If a pork roast must absorb

Chemistry
1 answer:
Black_prince [1.1K]3 years ago
7 0
Let us  assume propane was the fuel
C3H8(g) + 5O2(g) ---> 3CO2(g) + 4H2O(g) = 2217kJ
1 mole ofpropane produces 3 moles of CO2 
heat absorbed by pork = 0.11 x 2217
                                     = 243.87 kJ/mol
number of moles of propane = 1700kJ / 243.87 kJ/mol
                                              = 6.971 moles
1 mole of C3H8 = 3 moles ofCO2
6.971 moles of C3H8 = ?
3 x 6.971 = 20.913 moles of CO2
Convert to grams
mass = MW x mole
          = 44 x 20.913
          = 920.172g of CO2 emitted 
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Molar solubility is defined as moles of solute can be dissolved in 1L.

Ksp for NiS is defined as:

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Replacing:

Ksp = [3.27x10⁻¹¹M] [3.27x10⁻¹¹M]

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Balloon has a volume of 600-ml at temperature of 360 K. If the temperature of
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Answer:

V₂ ≈416.7 mL

Explanation:

This question asks us to find the volume, given another volume and 2 temperatures in Kelvin. Based on this information, we must be using Charles's Law and the formula. Remember, his law states the volume of a gas is proportional to the temperature.

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where V₁ and V₂ are the first and second volumes, and T₁ and T₂ are the first and second temperature.

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Substitute the values into the formula.

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Since we are solving for the second volume when the temperature is 250 K, we have to isolate the variable V₂. It is being divided by 250 K. The inverse o division is multiplication, so we multiply both sides by 250 K.

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The units of Kelvin cancel, so we are left with the units of mL.

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Let's round to the nearest tenth. The 6 in the hundredth place tells us to round to 6 to a 7.

  • 416.7 mL ≈V₂

The volume of the balloon at 250 K is approximately 416.7 milliliters.

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2 years ago
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