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2 years ago

Which phrase best describes a gravitational force?

Physics

2 answers:

ValentinkaMS [17]2 years ago

7 0

Answer:

I'm pretty sure it should be B

Explanation:

When you think of gravity, it pulls objects towards the ground by force. So, gravitational force should be pulling objects towards each other. Please let me know if this isn't right! I hope that helps! ^^

saveliy_v [14]2 years ago

5 0

Answer:

B or A Try your best to choose Between those 2 if not I'll help u

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An electron is held at a distance from a stationary, positively charged object.

salantis [7]

Answer:

A. Electric potential energy into kinetic energy

Explanation:

The electric potential energy of the charged particles is converted into kinetic energy as the electron is released.

5 0

3 years ago

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In physics 28.97 + 45.876 adds up to what?

myrzilka [38]

$28.97 + 45.876$

equals 74.846

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3 years ago

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It is easier to lift the load as the load is pushed towards the wheel in a wheelbarrow

Svetllana [295]

It’s easier to lift the wheelbarrow when the load is near the front because there isn’t any pressure near the back where the handles are.

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3 years ago

Suppose a NASCAR race car rounds one end of the Martinsville Speedway. This end of the track is a turn with a radius of approxim

sergiy2304 [10]

Answer:

10.53m/s²

Explanation:

Centripetal acceleration is the acceleration of an object about a circle. The formula for calculating centripetal acceleration is expressed by:

$a = \frac{v^2}{r}$

v is the velocity of the car = 24.5m/s

r is the radius of the track = 57.0m

Substitute the given values into the formula:

$a = \frac{24.5^2}{57} \\\\a = \frac{600.25}{57}\\ \\a = 10.53m/s^{2}$

Hence the centripetal acceleration of the race car is 10.53m/s²

6 0

3 years ago

How much heat energy must be added to 52kg Of water at 68°F to raise the temperature to 212°F? The specific heat capacity for wa

Anna [14]

Answer:

The amount of energy added to rise the temperature Q = 17413.76 KJ

Explanation:

Mass of water = 52 kg

Initial temperature $T_{1}$ = 68 °F = 20° c

Final temperature $T_{2}$ = 212 °F = 100° c

Specific heat of water $C = 4.186 \frac{KJ}{kg c}$

Now heat transfer Q = m × C × ( $T_{2}$ - $T_{1}$ )

⇒ Q = 52 × 4.186 × ( 100 - 20 )

⇒ Q = 17413.76 KJ

This is the amount of energy added to rise the temperature.

4 0

3 years ago