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ioda
3 years ago
9

What happens if you double the number of batteries used in a circuit? (Assume all of the batteries are the same.)

Chemistry
2 answers:
guajiro [1.7K]3 years ago
5 0
I think it is E. The voltage and current doubles. 
EleoNora [17]3 years ago
3 0
<h3><u>Answer;</u></h3>

E.The voltage and current doubles.

<h3><u>Explanation;</u></h3>
  • <em><u>From the Ohm's law, current through a conductor is directly proportional to the potential difference at constant temperature and pressure.</u></em>
  • Mathematically; I =V/R, where R is the resistance, I is the current and V is the voltage or the potential difference.
  • <em><u>Current is directly proportional to the voltage, thus and increase in voltage  causes an increases in the amount of current in a circuit and vice versa.</u></em>
  • <em><u>Thus, if you double the number of batteries used in a circuit the both the current and voltage doubles.</u></em>

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0.87708moldm-3

Explanation:

molar \: mass \: of \: cuso4 = 63.55 + 32.07 + 4(16.00) \\  =159.62gmol {}^{ - 1}   \\ mole(n) =  \frac{mass}{molar \: mass }  \\ n =  \frac{35}{159.62}  \\ n = 0.21927mol \\ molarity =  \frac{n}{v}  \\ molarity =  \frac{0.21927}{0.25} \\ molarity = 0.87708moldm {}^{ - 3}

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An arctic weather balloon is filled with 4.96 L of helium gas inside a prep shed. The temperature inside the shed is 6. °C. The
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<h3>Further explanation</h3>

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V₁ = 4.96 L

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Answer:

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Step 2: Balancing the equation

Pb(s) + AgNO3aq) → Ag(s) + Pb(NO3)2(aq)

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To balance the amount of NO3 on both sides, we have to multiply AgNO3 (on the left side) by 2.

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On the left side we have 2x Ag, on the right side we have 1x Ag.

To balance the amount of Ag on both sides, we have to multiply Ag (on the right side) by 2. Now the equation is balanced.

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8 0
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