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ohaa [14]
3 years ago
15

What scientist improved apon the telescope

Physics
1 answer:
Yakvenalex [24]3 years ago
3 0

Galileo Galilei is the scientist that improved apon the telescope


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Two identical objects in outer space have a head-on collision and stick together. If, before the collision, one had been moving
julia-pushkina [17]

Answer:

1.5 m/s

Explanation:

Momentum is conserved and conservation of momentum is

p₁ + p₂ = p'₁ + p'₂

or

m₁v₁ + m₂v₂ = m₁v'₁  + m₂v'₂

In our problem, after collision v'₁ will be equal to v'₂.

Since objects are identical m₁ = m₂

m(v₁+ v₂) = 2m x v'₁

(2m/s + 1m/s) = 2v'₁

v'₁ = v'₂ = 1.5 m/s

5 0
3 years ago
Does altitude has an effect on weight? PLEASE HELP!​
Studentka2010 [4]

Answer:

Yes

Explanation:

The farther something is from the center of mass of an object such as a planet, the lower the gravitational force between them

F = GMm/d²

4 0
2 years ago
A total charge of 4.70 is distributed on two metal spheres. When the spheres are 10 cm apart, they each feel a repulsive force o
Anna35 [415]

Answer:0.114 C

Explanation:

Given

Total 4.7 C is distributed in two spheres

Let q_1 and q_2 be the charges such that

q_1+q_2=4.7

and Force between charge particles is given by

F=\frac{kq_1q_2}{r^2}

4.7\times 10^11=\frac{9\times 10^9\times q_1\cdot q_2}{0.1^2}

q_1\cdot q_2=0.522

put the value of q_1

q_2\left ( 4.7-q_2\right )=0.522

q_2^2-4.7q_2+0.522=0

q_2=\frac{4.7\pm \sqrt{4.7^2-4\times 1\times 0.522}}{2}

q_2=0.114 C

thus q_1=4.586 C

3 0
3 years ago
A technique in which people use machines to learn how to control their bodies is known as __________.
Debora [2.8K]

Answer:

The technique in which people use machines to learn how to control their bodies is known as D, Biofeedback.

Explanation:

Biofeedback is a variety of different machines that help people learn how to control their bodies depending on their specific needs, varying from things like scalp sensors, electrocardiographs, electromyographs and more.

7 0
3 years ago
Read 2 more answers
An electron with a speed of 1.7 × 107 m/s moves horizontally into a region where a constant vertical force of 4.9 × 10-16 N acts
Alex Ar [27]

Answer:

 y = 77.74 10⁻⁵ m

Explanation:

For this exercise we can use Newton's second law

        F = m a

        a = F / m

        a = 4.9 10⁻¹⁶ / 9.1 10⁻³¹

        a = 0.538 10¹⁵ m / s

This is the vertical acceleration of the electron.

Now let's use kinematics to find the time it takes to move the

         x= 29 mm = 29 10⁻³ m

On the x axis

            v = x / t

            t = x / v

            t = 29 10⁻³ / 1.7 10⁷

            t = 17 10⁻¹⁰ s

Now we can look for vertical distance at this time.

            y = v_{oy} t + ½ a t²

            y = 0 + ½ 0.538 10¹⁵ (17 10⁻¹⁰)²

            y = 77.74 10⁻⁵ m

3 0
3 years ago
Read 2 more answers
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