Power is defined as rate of work done which means it is work done in 1 second of time
Now it is given that we have a horse that will give power 745.7 W
So it will do work of 745.7 J in 1 second of time
now if we wish to find the work done by horse in 0.55 s
so we can say
So it will do total work of 410.14 J in 0.55 s of time
K=Frictional Force/Normal Force
Normal force would be mg, since it's not on an incline.
Normal Force = 28 kg*9.8 m/s^2 = 274.4 N
200.3 N/274.4 N = 0.73
Answer:
<h3>Electricity is the flow of charges through a conductor. </h3>
<em>It happens when a force moves the first electron on a surface where they are free to </em><em>move</em><em>.</em><em> </em>
<em>From</em><em>~</em><em>C</em><em>h</em><em>a</em><em>r</em><em>m</em><em>i</em><em>n</em><em>g</em><em>l</em><em>e</em><em>x</em><em>~</em>
<em> </em>
Answer:
The distance moved by the block is 1.34 m
Explanation:
Given;
initial velocity of the block, u = 3 m/s
angle of inclination, θ = 20⁰
The net horizontal force acting on the block;
∑Fx = - mgsinθ
Apply Newton's second law of motion, to determine the constant acceleration of the block.
∑Fx = ma
- mgsinθ = ma
-gsinθ = a
Apply the following Kinematic equation, to determine how far up, the block moved before coming to rest.
![V_f^2 = V_i^2 + 2a(x_f -x_i)\\\\0 = V_i^2 + 2[-gsin \theta(x_f-0)]\\\\0 = V_i^2 - 2gsin \theta(x_f)\\\\ 2gsin \theta(x_f) = V_i^2\\\\x_f = \frac{V_i^2}{2gsin \theta} = \frac{(3)^2}{2 \ \times \ 9.8 \ \times \ sin(20)} = 1.34 \ m](https://tex.z-dn.net/?f=V_f%5E2%20%3D%20V_i%5E2%20%2B%202a%28x_f%20-x_i%29%5C%5C%5C%5C0%20%3D%20V_i%5E2%20%2B%202%5B-gsin%20%20%5Ctheta%28x_f-0%29%5D%5C%5C%5C%5C0%20%3D%20V_i%5E2%20%20-%202gsin%20%5Ctheta%28x_f%29%5C%5C%5C%5C%202gsin%20%5Ctheta%28x_f%29%20%3D%20V_i%5E2%5C%5C%5C%5Cx_f%20%3D%20%5Cfrac%7BV_i%5E2%7D%7B2gsin%20%5Ctheta%7D%20%3D%20%5Cfrac%7B%283%29%5E2%7D%7B2%20%5C%20%5Ctimes%20%5C%209.8%20%5C%20%5Ctimes%20%5C%20sin%2820%29%7D%20%3D%201.34%20%5C%20m)
Therefore, the distance moved by the block is 1.34 m
Explanation:
Porosity is the percentage of spaces,(hollow) within a rock or a material that can contain air or fluid. This can be used in geology( study of rocks), soil mechanics, engineering and pharmaceutics. Industrial CT scanning can be used to test for porosity of a substance. While permeability is the ability of water or other fluids to flow through a rock or material that has spaces ( that is, that are porous). This is also applicable in the fields of chemical engineering and geology.
