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liq [111]
3 years ago
14

Search and destroy christian

Engineering
2 answers:
bija089 [108]3 years ago
8 0

Answer:

the song?

Explanation:

Setler [38]3 years ago
3 0

Answer: ummmm wut?

Explanation:

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What do we need to travel farther distances in space
kakasveta [241]

Answer

Definitely a

Explanation:

Because OK yes the space suit is necessary and everything but u can't get to space without the shuttle

6 0
2 years ago
Read 2 more answers
What information you would gain by watching the video. Plz Help due today.
Archy [21]

Answer: It doesnt let me watch the link im sorry :(

Explanation:

3 0
2 years ago
An axial compressive load of 708 kN is applied to a cylindrical component, 81 mm in diameter and 418 mm long, made of aluminium.
dalvyx [7]

Answer:

The compressive stress of aplying a force of 708 kN in a 81 mm diamter cylindrical component is 0.137 kN/mm^2 or 137465051 Pa (= 137.5 MPa)

Explanation:

The compressive stress in a cylindrical  component can be calculated aby dividing the compressive force F to the cross sectional area A:

fc= F/A

If the stress is wanted in Pascals (Pa), F and A must be in Newtons and square meters respectively.

For acylindrical component the cross sectional area A is:

A=πR^

If the diameter of the component is 81 mm, the radius is the half:

R=81mm /2 = 40.5 mm

Then A result:

A= 3.14 * (40.5 mm)^2  = 5150.4 mm^2

In square meters:

A= 3.14 * (0.0405 m)^2  = 0.005150 m^2

Replacing 708 kN to the force:

fc= 708 kN / 5150.4 mm^2 = 0.137 kN/mm^2

Using the force in Newtons:

F= 70800 N

Finally the compressive stress in Pa is:

fc= 708000 / 0.005150 m^2 = 137465051 Pa = 137 MPa

4 0
3 years ago
The area under the moment diagram is shear force. a)-True b)-False
liberstina [14]

Answer:

False

Explanation:

as we know that V(x)=\frac{dM}{dx}\\ \\=> M(x) = \int\limits^x_o {V(x)} \, dx \\\\

=> Area under shear diagram gives the moment at any point but the reverse cannot be established from the same relation

8 0
3 years ago
A local zoo wants to keep track of how many pounds of food each of its three monkeys eats each day during a typical week. Write
Kryger [21]

Answer:

#include<iostream>

using namespace std;

int main()

{

  double data[3][5],avg,least,most,total;

  int leastNum,mostNum;

  for(int i=0;i<3;i++)

  {

      cout<<"Enter quantity of food for monkey "<<i+1<<":\n";

      for(int j=0;j<5;j++)

      {

          cout<<"Day "<<j+1<<": ";

          cin>>data[i][j];

      }

  }

  least = data[0][0];

  most = data[0][0];

  for(int i = 0;i<3;i++)

  {

      for(int j = 0;j<5;j++)

      {

          total+=data[i][j];

          if(data[i][j]>most)

          {

              most=data[i][j];

              mostNum=i+1;    

          }

          if(data[i][j]<least)

          {

              least=data[i][j];

              leastNum=i+1;

             

          }

      }

  }

  avg=total/5.0;

  cout<<"Average food eaten in a day by all the 3 monkeys: "<<avg<<endl;

  cout<<"Most amount of food eaten in a day: "<<most<<" by monkey: "<<mostNum<<endl;

  cout<<"Least amount of food eaten in a day: "<<least<<" by monkey: "<<leastNum<<endl;

  return 0;

}

6 0
3 years ago
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