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3 years ago

What is the best countermeasure against social engineering?

Engineering

1 answer:

Mkey [24]3 years ago

3 0

Answer:

Hello Monk7294!

Answer:

Employee education

Explanation:

The most important countermeasure for social engineering is employee education. All the employees should be trained to keep confidential data safe. As a part of security education, organizations have to provide timely orientation about their security policy to new employees. The security policy should address the consequences of the breaches.

- I Hope this helps Have an awesome day!

~ Chloe marcus <3

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Pendulum impacting an inclined surface of a block attached to a spring-Dependent multi-part problem assign all parts NOTE: This

Art [367]

Answer:

vA = -2.55 m/s

vB = 0.947 m/s

Explanation:

Given:-

- The initial angle of rope, α = 30°

- The angle of rope just before impact or wedge angle, θ = 20°

- The weight of sphere, Ws = 1-lb

- The initial position velocity, vi = 4 ft/s

- The coefficient of restitution, e = 0.7

- The weight of the wedge, Ww = 2-lb

- The spring constant, k = 1.8 lb/in

- The length of rope, L = 2.6 ft

Find:-

Determine the velocities of A and B immediately after the impact.

Solution:-

- We can first consider the ball ( acting as a pendulum ) to be isolated for study.

- There are no unbalanced fictitious forces acting on the sphere ball. Hence, we can reasonably assume that the energy is conserved.

- According to the principle of conservation for the initial point and the point just before impact.

Let,

vA : The speed of sphere ball before impact

Change in kinetic energy = Change in potential energy

ΔK.E = ΔE.P

0.5*ms* ( uA^2 - vi^2 ) = ms*g*L*( cos ( θ ) - cos ( α ) )

uA^2 = 2*g*L*( cos ( θ ) - cos ( α ) ) + vi^2

uA = √ [ 2*32*2.6*( cos ( 20 ) - cos ( 30 ) ) + 4^2 ] = √28.25822

uA = 5.316 ft/s

- The coefficient of restitution (e) can be thought of as a measure of the extent to which mechanical energy is conserved when an object bounces off a surface:

e^2 = ( K.E_after impact / K.E_before impact )

- The respective Kinetic energies are:

K.E_after impact = K.E_sphere + K.E_block

= 0.5*ms*vA^2 + 0.5*mb*vB^2

K.E_before impact = K.E = Ws*L*( cos ( θ ) - cos ( α ) )

= 1*2.6*( cos ( 20 ) - cos ( 30 ) )

= 0.1915 J

32*2*0.1915*0.7^2 = Ws*vA^2 + Wb*vB^2

6.00544 = vA^2 + 2*vB^2 ... Eq1

- From conservation of linear momentum we have:

vB = e*( uA - uB )*cos ( 20 ) + vA

vB = 0.7*( 5.316 - 0 )*cos ( 20) + vA

vB = 3.49678 + vA .... Eq 2

- Solve two equation simultaneously:

6.00544 = vA^2 + 2*(3.49678 + vA)^2

6.00544 = 3vA^2 + 13.98*vA + 24.455

3vA^2 + 14.8848*vA + 18.4495 = 0

vA = -2.55 m/s

vB = 0.947 m/s

5 0

4 years ago

A gas refrigeration system using air as the working fluid has a pressure ratio of 5. Air enters the compressor at 0°C. The high-

zimovet [89]

Answer:

(a) Effectiveness of the regenerator= 0.433

(b) The rate of heat removal=21.38 kW

Explanation:

The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.

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3 years ago

BE-40 What is a characteristic of a catamaran hull?

Nat2105 [25]

Answer:

A stable ride

Explanation:

A Catamaran hull is a form of sea craft invented by the Austronesian peoples, the invention of the Catamaran hull enabled these people to sail across the sea in their expansion to the islands of the Indian and Pacific Oceans. Catamaran has multiple hulls, usually two parallel hulls of equal size. This geometric feature gives the craft an increased stability because, it derives extra stability from its wide beam, in the place of a ballasted keel employed in a regular monohull sailboat. A Catamaran hull will require four times the force needed to capsize it, when compared to an equivalent monohull.

8 0

3 years ago

A fluid flows along the x axis with a velocity given by V = (xt) i ˆ, where x is in feet and t in seconds. (a) Plot the speed fo

nataly862011 [7]

Answer

See explanation for step by step procedures towards getting answers

Explanation:

Given that;

A fluid flows along the x axis with a velocity given by V = (xt) i ˆ, where x is in feet and t in seconds. (a) Plot the speed for 0 ≤ x ≤ 10 ft and t = 3 s. (b) Plot the speed for x = 7 ft and 2 ≤ t ≤ 4 s. (c) Determine the local and convective acceleration. (d) Show that the acceleration of any fluid particle in the flow is zero. (e) Explain physically how the velocity of a particle in this unsteady flow remains constant throughout its motion.

See attachments for further explanations

7 0

3 years ago

Read 2 more answers

Consider the flow field given by V ! =xy2^i− 1 3 y3^j+xyk ^. Determine (a) the number of dimensions of the flow, (b) if it is a

Basile [38]

Answer:

a) The flow has three dimensions (3 coordinates).

b) ∇V = 0 it is a incompressible flow.

c) ap = (16/3) i + (32/3) j + (16/3) k

Explanation:

Given

V = xy² i − (1/3) y³ j + xy k

a) The flow has three dimensions (3 coordinates).

b) ∇V = 0

then

∇V = ∂(xy²)/∂x + ∂(− (1/3) y³)/∂y + ∂(xy)/∂z

⇒ ∇V = y² - y² + 0 = 0 it is a incompressible flow.

c) ap = xy²*∂(V)/∂x − (1/3) y³*∂(V)/∂y + xy*∂(V)/∂z

⇒ ap = xy²*(y² i + y k) - (1/3) y³*(2xy i − y² j + x k) + xy*(0)

⇒ ap = (xy⁴ - (2/3) xy⁴) i + (1/3) y⁵ j + (xy³ - (1/3) xy³) k

⇒ ap = (1/3) xy⁴ i + (1/3) y⁵ j + (2/3) xy³ k

At point (1, 2, 3)

⇒ ap = (1/3) (1*2⁴) i + (1/3) (2)⁵ j + (2/3) (1*2³) k

⇒ ap = (16/3) i + (32/3) j + (16/3) k

3 0

4 years ago