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3 years ago

The chemical makeup of the contaminants and the types of bonds involved in their formation

Chemistry

1 answer:

andrey2020 [161]3 years ago

5 0

Answer:

Types of bonding in chemistry

There are three primary types of bonding: ionic, covalent, and metallic. Definition: An ionic bond is formed when valence electrons are transferred from one atom to the other to complete the outer electron shell.

Explanation:

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Human bone does not contain oxygen

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The CO2 produced in one round of the citric acid cycle does not originate in the acetyl carbons that entered that round. If the

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Answer:

It will require second round of the cycle to release $14C0_2$

Explanation:

Reason behind the requirement of second round of the cycle to release $CO_2$ -:

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2 years ago

What do dipole-dipole forces do?

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3 years ago

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Calcium carbide reacts with water to produce acetylene gas according to the following equation: CaC2(s) + 2H2O(l)C2H2(g) + Ca(OH

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Answer:

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Explanation:

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3 years ago

How many grams of aluminum are required to react with 35 mL of 2.0 M hydrochloric acid, HCl?__ HCl + __ Al --> __ AlCl3 + __

kiruha [24]

Answer:

0.6258 g

Explanation:

To determine the number grams of aluminum in the above reaction;

determine the number of moles of HCl
determine the mole ratio,
use the mole ratio to calculate the number of moles of aluminum.
use RFM of Aluminum to determine the grams required.

Moles of HCl

35 mL of 2.0 M HCl

2 moles of HCl is contained in 1000 mL

x moles of HCl is contained in 35 mL

$x \: mol \: = \: \frac{2 \: \times \: 35}{1000} \\ = 0.07 \: moles \:$

We have 0.07 moles of HCl.

Mole ratio

Balanced equation

6HCl(aq) + 2Al(s) --> 2AlCl3(aq) + 3H2(g)

Hence mole ratio = 6 : 2 (HCl : Al

but moles of HCl is 0.07, therefore the moles of Al;

$= \frac{2}{6} \times 0.07 \\ \: = 0.0233333 \: moles$

Therefore we have 0.0233333 moles of aluminum.

Grams of Aluminum

We use the formula;

$grams \: = moles \: \times \: rfm$

The RFM (Relative formula mass) of aluminum is 26.982g/mol.

Substitute values into the formula;

$= 0.0233333 \: moles \: \times \: 26.982 \: \frac{g}{mol} \\ = 0.625799 \: grams$

The number of grams of aluminum required to react with HCl is 0.6258 g.

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2 years ago