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Makovka662 [10]
3 years ago
7

Use the drawing below to answer the following question.

Physics
1 answer:
ss7ja [257]3 years ago
6 0

Answer:

A

Explanation:

Force =  mass x acceleration

if the force is constant for each of the boxes, the smaller a boxes mass the greater its acceleration while the force is applied

Therefore the smaller box will have a greater initial velocity and will slide the furthest before it stops.

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Someone please help me
Schach [20]

Answer:

300x480 teaspoons

Explanation:

when converting cups to teaspoons just multiply by 48

3 0
3 years ago
Read 2 more answers
The brightest, hottest, and most massive stars are the brilliant blue stars designated as spectral class O. If a class O star wi
aksik [14]

Answer:

2.77 * 10^5 m/s

Explanation:

Let us recall that kinetic energy is given by 1/2 mv^2

Where;

m = mass of the body

v = velocity of the body

In this case,

m = 3.38 * 10^31 kg

KE= 1.30 * 10^42 J

KE = 1/2 mv^2

v = √2KE/m

v = √2 * 1.30 * 10^42/3.38 * 10^31

v = √7.69 * 10^10

v = 2.77 * 10^5 m/s

4 0
3 years ago
What is the value of sin r and sin i in physics​
taurus [48]

Answer:

★The second law of refraction

The ratio of sine of angle of incidence to the sine of angle of refraction is a constant for a light of given colour and for a given pair of media. This law is also called Snell's law of refraction. If 'i' is the angle of incidence and 'r' is the angle of refraction then, Sin i/Sin r = constant

This constant value is called the refractive index of the second medium with respect to the first.

7 0
3 years ago
4. Two forces act on a 2 kg object as shown. What is the magnitude of the acceleration of the object?
aleksandrvk [35]

The resultant force on the object is

∑ <em>F</em> = 〈0, 8〉 N + 〈6, 0〉 N = 〈6, 8〉 N

which has a magnitude of

<em>F</em> = √((6 N)² + (8 N)²) = √(100 N²) = 10 N

By Newton's second law, the acceleration has magnitude <em>a</em> such that

<em>F</em> = <em>m a</em>

10 N = (2 kg) <em>a</em>

<em>a</em> = (10 N) / (2 kg)

<em>a</em> = 5 m/s²

so the answer is B.

4 0
3 years ago
An offshore oil well is 2 kilometers off the coast. The refinery is 4 kilometers down the coast. Laying pipe in the ocean is twi
shusha [124]

Answer:

Rectangular path

Solution:

As per the question:

Length, a = 4 km

Height, h = 2 km

In order to minimize the cost let us denote the side of the square bottom be 'a'

Thus the area of the bottom of the square, A = a^{2}

Let the height of the bin be 'h'

Therefore the total area, A_{t} = 4ah

The cost is:

C = 2sh

Volume of the box, V = a^{2}h = 4^{2}\times 2 = 128            (1)

Total cost, C_{t} = 2a^{2} + 2ah            (2)

From eqn (1):

h = \frac{128}{a^{2}}

Using the above value in eqn (1):

C(a) = 2a^{2} + 2a\frac{128}{a^{2}} = 2a^{2} + \frac{256}{a}

C(a) = 2a^{2} + \frac{256}{a}

Differentiating the above eqn w.r.t 'a':

C'(a) = 4a - \frac{256}{a^{2}} = \frac{4a^{3} - 256}{a^{2}}

For the required solution equating the above eqn to zero:

\frac{4a^{3} - 256}{a^{2}} = 0

\frac{4a^{3} - 256}{a^{2}} = 0

a = 4

Also

h = \frac{128}{4^{2}} = 8

The path in order to minimize the cost must be a rectangle.

8 0
3 years ago
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