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alex41 [277]
3 years ago
8

If an object has low acceleration it isn't moving very fast true or false

Physics
1 answer:
zhenek [66]3 years ago
5 0
Acceleration is an increased rate of speed or movement. So If an object has a low acceleration time it would not be moving very fast. So your question proves to be true.
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Which of the following has the greatest amount of kinetic energy a)slice of pizza b)a person at the top of the stairs c)wind d)a
Talja [164]

Answer:

c)wind

Explanation:

Wind from the given choices will have the greatest amount of kinetic energy.

Kinetic energy is the energy due to motion of a body. It is different from the energy at rest in a body.

  • Wind is air in motion.
  • Wind energy is a form of kinetic energy in motion.

A book on a table, a slice of pizza and a person at the top of the stairs are all at rest and will possess potential energy.

7 0
3 years ago
What is the momentum of a 73 person running with a speed of 2 m/s
NemiM [27]

Answer:

Explanation:

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6 0
4 years ago
The tires on your truck have 0.35 m radius. In a straight line, you drive 2600 m. What is the angular displacement of the tire,
Travka [436]
1) In a circular motion, the angular displacement \theta is given by
\theta =  \frac{S}{r}
where S is the arc length and r is the radius. The problem says that the truck drove for 2600 m, so this corresponds to the total arc length covered by the tire: S=2600 m. Using the information about the radius, r=0.35 m, we find the total angular displacement:
\theta =  \frac{2600 m}{0.35 m} =7428 rad

2) If we put larger tires, with radius r=0.60 m, the angular displacement will be smaller. We can see this by using the same formula. In fact, this time we have:
\theta =  \frac{2600 m}{0.60 m}=4333 rad
8 0
4 years ago
An inattentive driver is traveling 18.0 m/s when he notices a red light ahead. his car is capable of decelerating at a rate of 3
ryzh [129]

Speed of the car given initially

v = 18 m/s

deceleration of the car after applying brakes will be

a = 3.35 m/s^2

Reaction time of the driver = 0.200 s

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d_1 = v* t

d_1 = 18* 0.200 = 3.6 m

Now after applying brakes the distance covered by the car before it stops is given by kinematics equation

v_f^2 - v_i^2 = 2 a s

here

vi = 18 m/s

vf = 0

a = - 3.35

so now we will have

0^2 - 18^2 = 2*(-3.35)(s)

s = 48.35 m

So total distance after which car will stop is

d = d_1 + d_2

d = 48.35 + 3.6 = 51.95 m

So car will not stop before the intersection as it is at distance 20 m

3 0
4 years ago
The transfer of energy that occurs when a force is applied over a distance is
astra-53 [7]
The transfer of energy that occurs when a force is applied over a distance is WORK.
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4 years ago
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