Answer:
177.277amu
Explanation:
the total occuring isotopes for Hafnium is =6.
First isotope had an atomic weight of 173.940amu
Second isotope =175.941amu
Third isotope =176.943amu
Fourth isotope=177.944amu
Fifth isotope. =178.946amu
sixth isotope .179.947amu
<em>Avera</em><em>ge</em><em> </em><em>ato</em><em>mic</em><em> </em><em>wei</em><em>ght</em><em> </em><em>of</em><em> </em><em>Haf</em><em>nium</em><em>=</em><em> </em><em>sum</em><em> </em><em>of</em><em> </em><em>all</em><em> </em><em>the </em><em>atomi</em><em>c</em><em> </em><em>weights</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>iso</em><em>topes</em><em>/</em><em> </em><em>Tota</em><em>l</em><em> </em><em>occu</em><em>ring</em><em> </em><em>isotopes</em>
Thus, 173.940amu+175.941amu+176.943amu+177.944amu+178.946amu+179.947amu.= 1063.661amu
Average atomic weight= 1063.661amu /6 = 177.2768333amu
= 177.277amu to 3 decimal places.
Answer:
<h3>2Al+ Fe2O3 gives 2Fe + Al2O3. The given reaction is a redox reaction. As oxidation and reduction are taking place simultaneously.</h3>
Explanation:
like this...Identify oxidation and reduction with their agents:
<h3>•2Al+ Fe2O3 →2Fe + Al2O3</h3>
<h3>•Fe2O3 is reduced to Fe whereas Al is oxidized to Al2O3</h3>
<h3>In the above reaction:</h3>
<h3>Oxidizing agent:Fe2O3</h3>
<h3>Reducing agent:Al</h3>
I hope it's help you (◠‿・)—☆

An atom of this isotope contains 5 protons and 10-5=5 neutrons.

The answer is A. 1.67 × 10⁻²⁶ kg.
The answer would be B - homogeneous mixture