Gasses is the one because gas and gasses
http://century.rochester.k12.mn.us/cms/One.aspx?portalId=3086882&pageId=6133921
Hope this helps!
Please mark brainliest. :)
<u>61.25 grams</u> of CO can be formed from 35 grams of oxygen.
The molecular mass of oxygen is <u>16 gmol⁻¹</u>
The molecular mass of carbon monoxide is<u> 28 gmol⁻¹</u>
Explanation:
The molar mass of carbon monoxide is molar mass of C added to that of O;
12 + 16 = 28
= 28g/mol
The molar mass of oxygen is 16 g/mol while that of oxygen gas (O₂) is 32 g/mol
Since the ration oxygen to carbon monoxide is 1: 2 moles, we begin to find out how many moles of carbon monoxide are formed by 35 g of oxygen;
35/32 * 2
= 70/32 moles
Then multiply by the molar mass of carbon monoxide;
70/32 * 28
= 61.25 g
Answer:
The answer to your question is given below.
Explanation:
To prepare 50mL of 3M HCl, we must calculate the volume of the stock solution needed. This can obtained as follow:
Molarity of stock solution (M1) = 12M
Volume of stock solution needed (V1) =?
Molarity of diluted solution (M2) = 3M
Volume of diluted solution (V2) = 50mL
The volume of the stock solution needed can be obtained by using the dilution formula as shown below:
M1V1 = M2V2
12 x V1 = 3 x 50
Divide both side by 12
V1 = (3 x 50)/12
V1 = 12.5mL
The volume of the stock solution needed is 12.5mL
Therefore, to prepare 50mL of 3M HCl, we must measure 12.5mL of the stock solution i.e 12M HCl and then, add water to the mark in a 1L volumetric flask. Now we can measure out 50mL of the solution.
Scientists use carbon-14 to date ancient fossils.
Plants and animals absorb carbon-14 produced by cosmic rays. The ratio of C-14 to C-12 is constant when they are alive.
When they die, the C-14 decays to C-12, and the ratio changes.
Carbon-14 has a half-life of 5730 years. Thus, the object loses half its C-14 every 5730 years.
Scientists can use the C-14 to C-12 ratio to date fossils up to 70 000 years old.
