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Katyanochek1 [597]
3 years ago
9

Never mind i dont need help anymore

Physics
1 answer:
Usimov [2.4K]3 years ago
8 0
Yay good for you!!!!
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If you are given force and time, you can determine power if you can know...
Vera_Pavlovna [14]
If you're given the force and the length of time that the force acted,
then you can determine momentum, with units of [mass-length/time].

Without more information, you can't determine power, watts, energy,
joules, or distance. 
6 0
4 years ago
Read 2 more answers
Work out the following a) Find β = v/c for a person walking at 3 mile/hr and a truck moving at 65 mile/hr. (b) Find γ-1, where γ
balu736 [363]

Explanation:

It is given that,

Speed of the person, v = 3 mile/hr = 1.34 m/s

Speed of the truck, v' = 65 mile/hr = 29.05 m/s

(a) Since, \beta =\dfrac{v}{c}

For the person, \beta =\dfrac{1.34}{3\times 10^8}=4.47\times 10^{-9}    

For the truck, \beta =\dfrac{29.05}{3\times 10^8}=9.68\times 10^{-8}

(b) The relativistic factor is given by :

\gamma=\dfrac{1}{\sqrt{1-\beta^2}}

For very small velocity, \beta

\gamma=(1-\beta ^2)^{-1/2}\approx 1+\dfrac{1}{2}\beta ^2

\gamma-1=\dfrac{\beta^2}{2}

For the person :

\gamma-1=\dfrac{(4.47\times 10^{-9})^2}{2}=9.99\times 10^{-18}

For the person :

\gamma-1=\dfrac{(9.68\times 10^{-8})^2}{2}=4.68\times 10^{-15}

Hence, this is the required solution.

3 0
3 years ago
An LED with total power P tot = 960 mW emits UV light of wavelength 360 nm. Assuming the LED is 55% efficient and acts as an iso
Anit [1.1K]

Answer:

E_0=225.09N/C

Explanation:

We are given that

Power,Ptot=960mW=960\times 10^{-3}W

1mW=10^{-3} W

Wavelength,\lambda=360 nm=360\times 10^{-9} m

1nm=10^{-9} m

Distance,r=2.5 cm=2.5\times 10^{-2} m

1m=100 cm

Efficiency=55%

Power radiation emitted=\frac{55}{100}\times 960\times 10^{-3}=0.528W

Intensity,I=\frac{P}{4\pi r^2}

I=\frac{0.528}{4\pi(2.5\times 10^{-2})^2}=67.26W/m^2

Intensity,I=\frac{1}{2}c\epsilon_0E^2_0

E^2_0=\frac{2I}{c\epsilon_0}

Where \epsilon_0=8.85\times 10^{-12}

c=3\times 10^8 m/s

E_0=\sqrt{\frac{2I}{c\epsilon_0}}

E_0=\sqrt{\frac{2\times 67.26}{3\times 10^8\times 8.85\times 10^{-12}}}

E_0=225.09N/C

4 0
3 years ago
How many orbitals are allowed in a subshell if the angular momentum quantum number for electrons in that subshell is 3?
svp [43]

Answer:

7 orbitals are allowed in a sub shell if the angular momentum quantum number for electrons in that sub shell is 3.

Explanation:

We that different values of m for a given l provide the total number of ways in which a given s, p,d and f sub shells in presence of magnetic field can be arranged in space along x, y ,z- axis or total number of orbitals into which a given subshell can be divided.

    Range for given l lies between -l to +l .

The possible values of m are -3 , -2 , -1 , 0 , 1 ,2 , 3 .

    Total number of orbitals are 7.

4 0
3 years ago
As the temperature of an object increases, the wavelength of the brightest light emitted _______
alexira [117]

Answer:

option (B) decreases

Explanation:

According to the Wein's displacement law, the minimum wavelength of the radiated emission is inversely proportional to the absolute temperature of the body which emits radiation.

\lambda_{m}\alpha \frac{1}{T}

Where, T is the absolute temperature of the body and λm is the minimum wavelength of heat radiated.

Here, as the temperature increases, the wavelength decreases.

4 0
4 years ago
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