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evablogger [386]
3 years ago
10

The Drake Equation The Drake Equation Provides an estimate of how many planets there are in the Solar System that may harbor tec

hnically communicative life-forms. Provides an estimate of how many planets there are in our galaxy that may harbor technically communicative life-forms. Provides an estimate of how many planets there are in our galaxy that may harbor life-forms of any kind, no matter how primitive they may be. Provides an estimate of how many planets there are in the Universe that may harbor technically communicative life-forms.
Physics
2 answers:
Kitty [74]3 years ago
7 0

Answer:

Provides an estimate of how many planets there are in our galaxy that may harbor technically communicative life-forms.

Explanation:

A planet can be defined as a large celestial body having sufficient mass to allow for self-gravity and make it assume a nearly circular shape (hydrostatic equilibrium), revolves in an orbit around the Sun in the solar system and has a cleared neighborhood.

Basically, the planets are divided into two (2) main categories and these includes;

I. Outer planets: these planets are beyond the asteroid belt and comprises of jupiter, saturn, uranus and neptune, from left to right of the solar system.

II. Inner planets: these planets are the closest to the sun and comprises of mercury, venus, earth and mars.

These outer planets are made mostly of gases (hydrogen and helium) causing them to be less dense than the solid inner planets. These gases are generally known to be less dense in terms of physical properties.

Some examples of the planet are Mars, Venus, Earth, Mercury, Neptune, Jupiter, Saturn, Uranus, etc.

The Drake equation provides an estimate of how many planets there are in our galaxy that may harbor technically communicative life-forms. It is a probabilistic mathematical expression.

d1i1m1o1n [39]3 years ago
6 0

Answer:

The correct answer would be:

B.

the number of communicating civilizations in the cosmos

#PLATOFAM

Have a nice day!

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A) A spaceship passes you at a speed of 0.800c. You measure its length to be 31.2 m .How long would it be when at rest?
rosijanka [135]

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a

     l_o  =52 \  m

b

      l = 37.13 \ LY

Explanation:

From the question we are told that

    The  speed of the spaceship is  v  =  0.800c

    Here  c is the speed of light with value  c =  3.0*10^{8} \ m/s

    The  length is  l = 31.2 \  m

     The  distance of the star for earth is d = 145 \  light \  years

     The  speed is v_s = 2.90 *10^{8}

     

Generally the from the length contraction equation we have that

       l  =  l_o  \sqrt{1 -[\frac{v}{c } ]}

Now the when at rest the length is  l_o

So  

      l_o =\frac{l}{\sqrt{ 1 - \frac{v^2}{c^2 } } }

      l_o =\frac{ 31.2 }{ \sqrt{1 - \frac{(0.800c ) ^2}{c^2} } }

      l_o=52 \  m

Considering b  

  Applying above equation

            l  =l_o \sqrt{1 -  [\frac{v}{c } ]}

Here l_o  =145 \  LY(light \ years )

So

           l=145 *  \sqrt{1 -  \frac{v_s^2}{c^2 } }

            l =145 *  \sqrt{ 1 - \frac{2.9 *10^{8}}{3.0*10^{8}} }

            l = 37.13 \ LY

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