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Elodia [21]
4 years ago
12

Calculate the distance in km that Charlie runs if he maintains the average speed from question 2 for 1 hour

Physics
2 answers:
egoroff_w [7]4 years ago
5 0
Sorry, but what is question 2?
weqwewe [10]4 years ago
4 0

Distance covered by charlie= 2 km

Explanation:

we know that

d= v\times t

d= distance

t= time= 1 hour

v= velocity= 2 km/h

so distance d= 2 km/h (1 h)

d=2 km

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What is the magnitude of the resultant vector? Round
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Compare and contrast the inner and outer planets. (Must be in complete sentences) (At least 5 sentences).
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4 years ago
Charge Q is distributed uniformly throughout the volume of an insulating sphere of radius R = 4.00 cm. At a distance of r = 8.00
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2.62898\times 10^{-6}\ C/m^3

1979.99974\ N/C

Explanation:

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

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r = Distance = 8 cm

R = Radius = 4 cm

Electric field is given by

E=\dfrac{kQ}{r^2}\\\Rightarrow Q=\dfrac{Er^2}{k}\\\Rightarrow E=\dfrac{990\times 0.08^2}{8.99\times 10^{9}}\\\Rightarrow Q=7.04783\times 10^{-10}\ C

Volume charge density is given by

\sigma=\dfrac{Q}{\dfrac{4}{3}\pi R^3}\\\Rightarrow \sigma=\dfrac{7.04783\times 10^{-10}}{\dfrac{4}{3}\pi (0.04)^3}\\\Rightarrow \sigma=2.62898\times 10^{-6}\ C/m^3

The volume charge density for the sphere is 2.62898\times 10^{-6}\ C/m^3

E=\dfrac{kQr}{R^3}\\\Rightarrow E=\dfrac{8.99\times 10^9\times 7.04783\times 10^{-10}\times 0.02}{0.04^3}\\\Rightarrow E=1979.99974\ N/C

The magnitude of the electric field is 1979.99974\ N/C

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