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larisa [96]
2 years ago
12

“Different periods in human history are named for the materials used to make tools. Dr. Franklin is searching through layers of

soil, looking for tools made by humans. After screening the top layer of soil, he uses a magnet to help speed up the search.”
Which type of location is Dr. Franklin most likely searching?
A) a cave from before the Stone Age
B) a Stone Age cave
C) a Bronze Age battle site
D) an Iron Age farm​
Chemistry
2 answers:
Dafna1 [17]2 years ago
7 0

Answer:

D

Explanation:

Got it right on edge

kipiarov [429]2 years ago
3 0

Answer:

Iron age farm

Explanation:

edge 2020

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Whitepunk [10]

Answer: There are 4.8 x 1024 hydrogen atoms in 2.0 moles of CH4

6 0
2 years ago
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What was the main reason why Alfred Wegener's theory about the movement of the continents was dismissed in 1912?
eduard

Answer:

His map of the ocean floor did not support his theory

Explanation:

  • Alfred Wegner was a great scientist
  • He observed the plate tectonics of earth and described it in a theory.
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8 0
2 years ago
A chromate ion consist of four oxygen atom bonded to be a chromium atom. It has two extra electrons. the formula for this
natali 33 [55]

Answer:

Cr04^2-

Explanation:

 

6 0
3 years ago
A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm,
inna [77]

Answer:

3.676 L.

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

  • If n and P are constant, and have different values of V and T:

(V₁T₂) = (V₂T₁)

  • Knowing that:

V₁ = 3.5 L, T₁ = 25°C + 273 = 298 K,

V₂ = ??? L, T₂ = 40°C + 273 = 313 K,

  • Applying in the above equation

(V₁T₂) = (V₂T₁)

∴ V₂ = (V₁T₂)/(T₁) = (3.5 L)(313 K)/(298 K) = 3.676 L.

7 0
3 years ago
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How do I calculate the standard enthalpy change for the following reaction at 25 °C ?
ladessa [460]
MgCl2(s) + H2O(l) → MgO(s) + 2 HCl(g) 

Using the standard enthalpies of formation given in the source below: 

(−601.24 kJ) + (2 x −92.30 kJ) − (−641.8 kJ) − (−285.8 kJ) = +141.76 kJ 
So: 

MgCl2(s) + H2O(l) → MgO(s) + 2 HCl(g), ΔH = +141.76 kJ
4 0
3 years ago
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