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Morgarella [4.7K]
3 years ago
13

Please help me, I don’t know the answer

Physics
2 answers:
AfilCa [17]3 years ago
6 0

Answer:

I'm pretty sure it is D:2.

Explanation:

Since potential energy is basically something sitting still. If not C then D.

den301095 [7]3 years ago
3 0
I also think it’s D

Hopefully we helped
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Starting the moon's cycle with the new moon phase, what phase will it be in after about a week?
sergey [27]
The waxing crescent moon I believe 
5 0
3 years ago
The collision between a hammer and a nail can be considered to be approximately elastic. estimate the kinetic energy acquired by
Setler [38]

Here we can use momentum conservation as in this type of collision there is no external force on it

m_1v_{1i} + m_2v_{2i} = m_1 v_{1f} + m_2v_{2f}

now here we can say

m_1 = 10 g

v_{1i} = 0

m_2 = 550 g

v_{2i} = 3.5 m/s

now here we can say

10*0 + 550 * 3.5 = 10 v_{1f} + 550 v_{2f}

192.5 = v_{1f} + 55 v_{2f}

now by coefficient of restitution

for elastic collision we know that e = 1

v_{2f} - v_{1f} = e(v_{1i} - v_{2i})

v_{2f} - v_{1f} = 0 - 3.5

now by solving the two equation

56v_{2f} = 189

v_{2f} = 3.375 m/s

also we know that

v_{1f} = v_{2f} + 3.5 = 3.375 + 3.5 = 6.875 m/s

so final speed of the nail is 6.875 m/s


6 0
2 years ago
Read 2 more answers
A fisherman noticed that a wave strikes the boat side every 5 seconds. The distance between two consecutive crest is 1.5m. What
GrogVix [38]
5/1.5=7 I think that is the answer
8 0
3 years ago
1. Calculate the momentum of each car before the collision: SHOW YOUR WORK!
a_sh-v [17]

Answer:

Momentum of red car = 5kgm/s

Momentum of blue car = 0kgm/s

Explanation:

Momentum = mass × velocity

For the red car

Mass = 1kg

Velocity = 5m/s

Momentum of the red car = 1kg × 5m/s

Momentum of the red car = 5kgm/s

For the blue car.

Mass = 1kg

Velocity = 0m/s(shows that the blue car is stationery)

Momentum = 1kg ×0m/s

Momentum of the blue car = 0kgm/s

3 0
3 years ago
The bones of the forearm (radius and ulna) are hinged to the humerus at the elbow. The biceps muscle connects to the bones of th
SVETLANKA909090 [29]

Answer:

F_b  = 1647.92 N

Explanation:

Given:

length of the arm, r = 0.465 m

distance of forearm from elbow, r' = 2.15 cm = 0.0215 m

Mass of the forearm, M = 2.45 kg

Mass of the object, m = 6.55 kg

Let, the Force by bicep be, F_b

under the motionless condition, the net moment about elbow is zero

thus,

F_b × 0.0215 - Mg × (0.465/2) - mg × (0.465) = 0

or

F_b × 0.0215 - 2.45 × 9.8 × (0.465/2) - 6.55 × 9.8 × (0.465) = 0

or

F_b × 0.0215 - 5.582 - 29.848 = 0

or

F_b  = 1647.92 N

hence, the force exerted by the elbow is 1647.92 N

4 0
3 years ago
Read 2 more answers
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