Answer:
Gamit ang graphic organizer na concept po punan niyo po ang mga sangay na ito at magpapakita ng paggalang sa kapwa kalaro
Btw only someone who is nice will answer tour question. You can't expect for explanition when the question is only worth 5 points. Not trying to be mean sorry if i am being mean
Answer:D
Explanation:Electric power=I*I*R
=12*12*100
=14400watts
Answer:
Y component = 32.37
Explanation:
Given:
Angle of projection of the rocket is, ![\theta=33.6](https://tex.z-dn.net/?f=%5Ctheta%3D33.6)
Initial velocity of the rocket is, ![u=58.5](https://tex.z-dn.net/?f=u%3D58.5)
A vector at an angle
with the horizontal can be resolved into mutually perpendicular components; one along the horizontal direction and the other along the vertical direction.
If a vector 'A' makes angle
with the horizontal, then the horizontal and vertical components are given as:
![A_x=A\cos \theta(\textrm{Horizontal or X component})\\A_y=A\sin \theta(\textrm{Vertical or Y component})](https://tex.z-dn.net/?f=A_x%3DA%5Ccos%20%5Ctheta%28%5Ctextrm%7BHorizontal%20or%20X%20component%7D%29%5C%5CA_y%3DA%5Csin%20%5Ctheta%28%5Ctextrm%7BVertical%20or%20Y%20component%7D%29)
Here, as the velocity is a vector quantity and makes an angle of 33.6 with the horizontal, its Y component is given as:
![u_y=u\sin \theta](https://tex.z-dn.net/?f=u_y%3Du%5Csin%20%5Ctheta)
Plug in the given values and solve for
. This gives,
![u_y=(58.5)(\sin 33.6)\\u_y=58.5\times 0.55339\\u_y=32.373\approx32.37(\textrm{Rounded to two decimal places})](https://tex.z-dn.net/?f=u_y%3D%2858.5%29%28%5Csin%2033.6%29%5C%5Cu_y%3D58.5%5Ctimes%200.55339%5C%5Cu_y%3D32.373%5Capprox32.37%28%5Ctextrm%7BRounded%20to%20two%20decimal%20places%7D%29)
Therefore, the Y component of initial velocity is 32.37.
Answer: 3.33 m/s
Explanation:
Assuming the questions is to convert 12 km/h to meter per second (m/s), let's begin:
In order to make the conversion, we have to know the following:
![1 km=1000 m](https://tex.z-dn.net/?f=1%20km%3D1000%20m)
And:
![1 h=3600 s](https://tex.z-dn.net/?f=1%20h%3D3600%20s)
Keeping this in mind, we can make the conversion:
![12 \frac{km}{h} \frac{1000 m}{1 km} \frac{1h}{3600 s}](https://tex.z-dn.net/?f=12%20%5Cfrac%7Bkm%7D%7Bh%7D%20%5Cfrac%7B1000%20m%7D%7B1%20km%7D%20%5Cfrac%7B1h%7D%7B3600%20s%7D)
Then:
![12 \frac{km}{h}= 3.33 \frac{m}{s}](https://tex.z-dn.net/?f=12%20%5Cfrac%7Bkm%7D%7Bh%7D%3D%203.33%20%5Cfrac%7Bm%7D%7Bs%7D)