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KonstantinChe [14]
2 years ago
9

How much potassium nitrate, KNO3, would completely dissolve in 100g of water at 40℃?

Physics
1 answer:
dem82 [27]2 years ago
5 0
Why does this same one keep popping up what ever I think it is 65 a and c are definitely not it so if your going to guess go with b or d but I’m purée sure it’s d
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A stone is thrown straight up from the edge of a roof, 925 feet above the ground, at a speed of 20 feet per second. Remembering
Black_prince [1.1K]
<h2>Answer: 469 feet</h2>

Explanation:

This problem is a good example of Vertical motion, where the main equation for this situation is:

y=y_{o}+V_{o}t-\frac{1}{2}gt^{2} (1)

Where:

y is the height of the stone at 6s (the value we want to find)

y_{o}=925ft is the initial height of the stone

V_{o}=20ft/s is the initial velocity of the stone

t=6s is the time  at which we need to find the height

g=32ft/s^{2} is the acceleration due to gravity

Having this clear, let's find y from (1):

y=925ft+(20ft/s)(6s)-\frac{1}{2}(32ft/s^{2})(6s)^{2} (2)

Finally:

y=469ft This is the height of the stone at t=6s

4 0
3 years ago
The basic barometer can be used to measure the height of a building. If the barometric readings at the top and the bottom of a b
erma4kov [3.2K]

Answer:

h = 269.6 m

Explanation:

Pressure at the bottom of the building and at the top of the building must be related as

P_{top} = P_{bottom} - \rho g h

P_{top} = 730 mm Hg

P_{bottom} = 755 mm Hg

now we will have

(755 \times 10^{-3})(13.6 \times 10^3)(9.81) = P_{bottom}

P_{bottom} = 1.007 \times 10^5 Pa

P_{top} = (730\times 10^{-3})(13.6 \times 10^3)(9.81)

P_{top} = 0.974 \times 10^5

now we have

(1.007 - 0.974)\times 10^5 = 1.25 (9.81) h

h = 269.6 m

7 0
3 years ago
A person starts at the origin and then walks 6 m to the west, and then 8 m south.
zmey [24]

please mark brainliest

Explanation:

Let the east direction to be i^ and north direction be j^.

Thus displacement of the man   S=8i^+6j^

So, magnitude of displacement  ∣S∣=62+82=100=10 m

5 0
3 years ago
Explain what happens to the particles in a substance during a physical change.
Bingel [31]
During Physical Change there would be a re-arrangements of atoms or molecules, changes of the arrangement may be change in the distance between atoms or molecules, change in the crystal form, .....etc 

for example: water when heated it undergoes a Physical Change and turn into vapor, this means the heat cause the distance between water molecules to increase, so it transferred from the liquid form to the gas form. 

NOTE that in Physical Change there is no change in the chemical structure and the material retains all its chemical properties, and no new compounds are produced. 

again, A physical change is any change not involving a change in the substance's chemical identity. Matter undergoes chemical change when the composition of the substances changes: one or more substances combine or break up (as in a relationship) to form new substances.Physical changes occur when objects undergo a change that does not change their chemical nature. A physical change involves a change in physical properties. Physical properties can be observed without changing the type of matter. Examples of physical properties include: texture, shape, size, color, odor, volume, mass, weight, and density. 

BUT in Chemical Change ( or Chemical Reaction ) there would be change in the chemical nature of the material undergoing a Chemical Change with the production of new compounds.
5 0
3 years ago
Read 2 more answers
A family car has a mass of 1400 kg. In an accident it hits a wall and goes from a speed of 27 m/s to a standstill in 1.5 seconds
horrorfan [7]

Answer:

The force has been reduced by 8018 N

Explanation:

The impulse exerted on the car during the crash is equal to the product of the force exerted and the duration of the collision, and it is also equal to the change in momentum of the car. So we can write:

F\Delta t = m\Delta v

where:

F is the force exerted on the car

\Delta t is the duration of the collision

m = 1400 kg is the mass of the car

\Delta  v=-27 m/s is the change in velocity of the car

We can re-write the equation as

F=\frac{m\Delta v}{\Delta t}

In the 1st collision, the time is 1.5 seconds, so the force is

F_1=\frac{(1400)(-27)}{1.5}=-25,200 N

In the 2nd collision, the time is increased to 2.2 seconds, so the force is

F_2=\frac{(1400)(-27)}{2.2}=-17,182 N

Therefore, the force has been reduced by:

F_2-F_1=-17,182-(-25,200)=8018 N

4 0
3 years ago
Read 2 more answers
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