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marusya05 [52]
3 years ago
13

chlorine gas forms went to green out of the shower and electron what type of bonding is present in chlorine gas

Chemistry
1 answer:
sattari [20]3 years ago
4 0
The answer is Chemical bounding
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PLEASE HELP
earnstyle [38]
Answer:
               Cp  =  0.093 J.g⁻¹.°C⁻¹
Solution:

The equation used for this problem is as follow,

                                                  Q  =  m Cp ΔT   ----- (1)

Where;
            Q  =  Heat  =  300 J

            m  =  mass  =  267 g

            Cp  =  Specific Heat Capacity  =  ??

            ΔT  =  Change in Temperature  =  12 °C

Solving eq. 1 for Cp,

                                 Cp  =  Q / m ΔT


Putting values,
                                 Cp  =  300 J / (267 g × 12 °C)

                                 Cp  =  0.093 J.g⁻¹.°C⁻¹
6 0
3 years ago
Urea makes up a significant amount of urine, and is the chemical that the body uses to rid cells of unwanted carbon dioxide and
Ira Lisetskai [31]
Urea is highly soluble in water. When it is allowed to dissolve in water in the presence of heat, it will yield ammonia and carbon dioxide. The reaction is shown below:

<span>NH2-CO-NH2 + H2O </span>⇒ 2 NH3 + CO2

As you can observe in the stoichiometric equations, 1 molecule of water can dissolve with 1 mole of urea.
3 0
3 years ago
three students made multiple weighings of a copper cylinder each using a different balance. Describe the accuracy and precision
ch4aika [34]
I think that you have put up an incomplete question. However, i am answering the question based on my research and knowledge. 

Lissa- accuracy and precision are both low
Lamont- accuracy and precision are definitely high
<span>Leigh Anne- accuracy is low but precision is definitely high.
</span>
I hope that this is the answer that you were looking for and the answer has definitely come to your desired help.
3 0
3 years ago
Pleaseee helpppp!!!!!!!!
Katarina [22]

Answer:

a covalent would be the two that are nonmetals

7 0
3 years ago
A 24.00 mL sample of a solution of Pb(ClO3)2 was diluted with water to 52.00 mL. A 17.00 mL sample of the dilute solution was fo
lara [203]

Answer:

0.238 M

Explanation:

A 17.00 mL sample of the dilute solution was found to contain 0.220 M ClO₃⁻(aq). The concentration is an intensive property, so the concentration in the 52.00 mL is also 0.220 M ClO₃⁻(aq). We can find the initial concentration of ClO₃⁻ using the dilution rule.

C₁.V₁ = C₂.V₂

C₁ × 24.00 mL = 0.220 M × 52.00 mL

C₁ = 0.477 M

The concentration of Pb(ClO₃)₂ is:

\frac{0.477molClO_{3}^{-} }{L} \times \frac{1molPb(ClO_{3})_{2}}{2molClO_{3}^{-}} =0.238M

6 0
3 years ago
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