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3 years ago

What is the bond dissociation energy for breaking all the bonds in a mole of o2 molecules?

Chemistry

1 answer:

djverab [1.8K]3 years ago

8 0

<h3>Answer:</h3>

498 kj/mol

<h3>Explanation:</h3>

Chemical reactions occur as a result of bond breaking and bond formation.
The bonds in reactants are broken and atoms are rearranged to form new bonds.
During bond breaking energy is absorbed to break the bonds of reactants while bond formation involves the release of energy during the formation of new bonds.

In our case;

In 1 mole of the Oxygen molecule, there is one O=O bond

Energy absorbed to break O=O is 498 kJ/mol

Therefore, the ΔH required to break all the bonds in one mole of Oxygen(O₂) molecules is 498kJ/mol.

Note that, bond breaking is endothermic since energy is absorbed from the surroundings.

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the hemiacetal below is treated with 18o-labeled methanol (ch3o*h) and acid. where will the label appear in the products?

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The 18o-labeled methanol (CH3O*H) will appear in the products side at position b.

<h3>Position of 18o-labeled methanol in the products</h3>

The 18O label will appear at position b in the product as indicated in the image.

This methoxy group in the product formed in position b comes from the 18O-labeled methanol (CH3OH).

While the oxygens at positions a and c in the product come from the unlabeled hemiacetal.

Thus, the 18o-labeled methanol (CH3O*H) will appear in the products side at position b.

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1 year ago

Calculate the work done when an ideal gas expands isothermally and reversibly in a piston and cylinder assembly for expansion of

pantera1 [17]

Answer:

$W=5743.1077\ J$

Explanation:

The expression for the work done is:

$W=RT \ln \left( \dfrac{P_1}{P_2} \right)$

Where,

W is the amount of work done by the gas

R is Gas constant having value = 8.314 J / K mol

T is the temperature

P₁ is the initial pressure

P₂ is the final pressure

Given that:

T = 300 K

P₁ = 10 bar

P₂ = 1 bar

Applying in the equation as:

$W=8.314\times 300 \ln \left( \dfrac{10}{1} \right)$

$W=300\times \:8.314\ln \left(10\right)$

$W=2.30258\times \:2494.2$

$W=5743.1077\ J$

5 0

3 years ago

A sample of hydrogen gas collected over water occupied 30.0 mL at 24 °C on a day when the atmospheric pressure was 736 Torr. Wha

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Answer:0.026ml

Explanation:

Details are found in the image attached. We must subtract the saturated vapour pressure of hydrogen gas at the given temperature from the total pressure of the hydrogen gas collected over water to obtain the actual pressure of hydrogen gas and substitute the value obtained into the general gas equation. The dry hydrogen gas has no saturated vapour pressure hence the value is substituted as given. All temperatures must be converted to Kelvin before substitution.

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3 years ago

Acetylene gas is often used in welding torches because of the very high heat produced when it reacts with oxygen gas, producing

rodikova [14]

Answer:

0.225 mol = 0.23 mol to 2 significant figures

Explanation:

Calculate the moles of oxygen needed to produce 0.090 mol of water

The equation of the reaction is given as;

2 C2H2 + 5 O2 --> 4 CO2 + 2 H2O

From the equation of the reaction;

5 mol of O2 produces 2 mol of H2O

x mol of O2 produces 0.090 mol of H2O

5 = 2

x = 0.090

x = 0.090 * 5 / 2

x = 0.225 mol

8 0

3 years ago