All categories

3 years ago

1. What is the difference between thermal energy and heat? Give an example.

Physics

1 answer:

Arisa [49]3 years ago

5 0

Answer:

when you run u get tied

Explanation:

I do not now this one

You might be interested in

A helium-filled balloon occupies a volume of 15 cubic meters at sea level. the balloon is released and raises to a point in the

Elena L [17]

According to Boyle’s law, For a fixed amount of an ideal gas kept at a fixed temperature, P (pressure) and V (volume) are inversely proportional.

Therefore,

$P_{1} V_{1} =P_{2} V_{2}$

Given $P_{1} = 1 atm$ , $V_{1} = 15 \ cubic \ meter$ and $P_{2} = 0.75\ atm$ .

Thus,

$V_{2} = \frac{P_{1}\times V_{1} }{ P_{2} } = \frac{1\times 15}{0.75} =20 m^3$

5 0

3 years ago

Chris is about to do an experiment to measure the density of water at several temperatures. His teacher has him prepare and sign

Marina86 [1]

Inspect the glassware for cracks or chips prior to beginning the lab.

7 0

3 years ago

Read 2 more answers

A toroid having a square cross section, 5.49 cm on a side, and an inner radius of 18.1 cm has 450 turns and carries a current of

joja [24]

Answer:

(a) 4.27 x 10^-4 Telsa

(b) 3.28 x 10^-4 Telsa

Explanation:

side of square, a = 5.49 cm

inner radius, r = 18.1 cm = 0.181 m

number of turns,N = 450

current, i = 0.859 A

(a)

The magnetic field due to a solenoid due to inner radius is

$B = \frac{\mu_{0}Ni}{2\pi r_{inner}}$

$B = \frac{4\pi\times 10^{-7}\times 450\times 0.859}{2\pi \times 0.181}$

B = 4.27 x 10^-4 Telsa

(b)

The outer radius is R = 18.1 + 5.49 = 23.59 cm = 0.236 m

The magnetic field due to the outer radius is

$B = \frac{\mu_{0}Ni}{2\pi r_{outer}}$

$B = \frac{4\pi\times 10^{-7}\times 450\times 0.859}{2\pi \times 0.236}$

B = 3.28 x 10^-4 Tesla

7 0

3 years ago

The amount of gas that a helicopter uses is directly proportional to the number of hours spent flying. the helicopter flies for

igomit [66]

Answer:

The helicopter uses 35 gallons to fly for 5 hours.

Explanation:

The amount of gas that a helicopter uses for flying varies directly proportional to the number of hours spent flying.

g ∝ T

where g represents amount of gas and T time of flight.

Then,

$\therefore \frac{g_1}{g_2}=\frac{T_1}{T_2}$

The helicopter files 4 hours and uses 28 gallons of fuel.

Here, g₁= 28 gallons, T₁=4 hours

g₂=?, T₂=5 hours.

$\therefore \frac{g_1}{g_2}=\frac{T_1}{T_2}$

$\Rightarrow \frac{28}{g_2}=\frac{4}{5}$

⇒28×5= g₂×4

⇒ g₂×4=28×5

$\Rightarrow g_2=\frac{28\times 5}{4}$

$\Rightarrow g_2=35$ gallons

The helicopter uses 35 gallons to fly for 5 hours.

5 0

3 years ago

PLEASE ANSWER! WILL MARK BRAINLIEST!

Angelina_Jolie [31]

The first one would be thermal energy

8 0

3 years ago