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3 years ago

Need some help with this!

Physics

2 answers:

zvonat [6]3 years ago

8 0

Answer: what’s it asking

Explanation:

MariettaO [177]3 years ago

4 0

Answer:The Earth is shown as a circle. Equator is shown and labeled at 0 degrees. 30 degrees north and south latitudes are shown and labeled. 60 degrees north and south latitudes are shown and labeled. Curved arrows are shown pointing from 30 degrees north and south latitudes towards the equator.

What best describes these winds?

Polar easterlies that curve due to air above poles being relatively cooler

Jet streams that curve due to air above equator being relatively warmer

Trade winds blowing in a curved manner due to the rotation of Earth

Polar westerlies blowing in a curved manner due to Coriolis Effect.

Is this the question to it?

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Why are coal,nuclear,oil,and natural gas determined to be non-renewable types of energy resources

IrinaVladis [17]

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Once used as a energy source they cannot be charged/used again.

Explanation:

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3 years ago

According to the Big Bang Theory, how long ago did the universe expand explosively into existence

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About 13.7 billion years ago

The Big Bang Theory states that the universe started about 13.7 billion years ago, and before that, everything was in 1 singularity.

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3 years ago

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The element that has an average amu of 40 is represented by the symbol Zr on the Periodic Table of Elements. True False Question

Gnom [1K]

Answer:

False

Explanation:

Becuase the average amu of 40 is represented

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3 years ago

Three masses (3 kg, 5 kg, and 7 kg) are located in the xy-plane at the origin, (2.3 m, 0), and (0, 1.5 m), respectively.

Artist 52 [7]

Answer:

a) C.M $=(\bar x, \bar y)=(0.767,0.7)m$

b) $(x_4,y_4)=(-1.917,-1.75)m$

Explanation:

The center of mass "represent the unique point in an object or system which can be used to describe the system's response to external forces and torques"

The center of mass on a two dimensional plane is defined with the following formulas:

$\bar x =\frac{\sum_{i=1}^N m_i x_i}{M}$

$\bar y =\frac{\sum_{i=1}^N m_i y_i}{M}$

Where M represent the sum of all the masses on the system.

And the center of mass C.M $=(\bar x, \bar y)$

Part a

$m_1= 3 kg, m_2=5kg,m_3=7kg$ represent the masses.

$(x_1,y_1)=(0,0),(x_2,y_2)=(2.3,0),(x_3,y_3)=(0,1.5)$ represent the coordinates for the masses with the units on meters.

So we have everything in order to find the center of mass, if we begin with the x coordinate we have:

$\bar x =\frac{(3kg*0m)+(5kg*2.3m)+(7kg*0m)}{3kg+5kg+7kg}=0.767m$

$\bar y =\frac{(3kg*0m)+(5kg*0m)+(7kg*1.5m)}{3kg+5kg+7kg}=0.7m$

C.M $=(\bar x, \bar y)=(0.767,0.7)m$

Part b

For this case we have an additional mass $m_4=6kg$ and we know that the resulting new center of mass it at the origin C.M $=(\bar x, \bar y)=(0,0)m$ and we want to find the location for this new particle. Let the coordinates for this new particle given by (a,b)