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3 years ago

Need some help with this!

Physics

2 answers:

zvonat [6]3 years ago

8 0

Answer: what’s it asking

Explanation:

MariettaO [177]3 years ago

4 0

Answer:The Earth is shown as a circle. Equator is shown and labeled at 0 degrees. 30 degrees north and south latitudes are shown and labeled. 60 degrees north and south latitudes are shown and labeled. Curved arrows are shown pointing from 30 degrees north and south latitudes towards the equator.

What best describes these winds?

Polar easterlies that curve due to air above poles being relatively cooler

Jet streams that curve due to air above equator being relatively warmer

Trade winds blowing in a curved manner due to the rotation of Earth

Polar westerlies blowing in a curved manner due to Coriolis Effect.

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What is the difference between transverse waves and longitudinal waves?

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D.transverse waves move perpendicular and longitudinal waves move parallel to the direction of energy movement..

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A ball is dropped off a building and falls past a window that is 2.2m long. If it takes .28s for the ball to cross the window wh

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0.616 is the distance from the top
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2 years ago

A sprinter starts from rest and reaches a speed of 15 m/s in 4.25 s. Find his acceleration

kakasveta [241]

Answer:

a=3.53 m/s^2

Explanation:

Vo=0 m/s (because he is not moving at the start)

V1=15 m/s

t= 4.25 s

a = (V1-Vo) / t = 15/4.25 = 3.53 m/s^2

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3 years ago

Giving quadrilateral a(2,-1 ) b ( 1,3) c(6,5) d(7,1) you want to prove that it is a parallelogram by showing opposite sides are

solong [7]

Answer:

Opposite sides are congruent (AB = DC).

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3 years ago

The charges and coordinates of two charged particles held fixed in the xy plane are: q1 = +3.3 µc, x1 = 3.5 cm, y1 = 0.50 cm, an

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1) First of all, we need to find the distance between the two charges. Their distance on the xy plane is
$d= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$
substituting the coordinates of the two charges, we get
$d= \sqrt{(3.5+2)^2+(0.5-1.5)^2}=5.6~cm=0.056~m$

2) Then, we can calculate the electrostatic force between the two charges $q_1$ and $q_2$ , which is given by
$F=k_e \frac{q_1 q_2}{d^2}$
where $k_e=8.99\cdot10^{9} Nm^2C^{-2}$ is the Coulomb's constant.
Substituting numbers, we get
$F=8.99\cdot10^{9} Nm^2C^{-2} \frac{(3.3\cdot10^{-6}~C) (-4\cdot10^{-6}~C)}{(0.056~m)^2} =-37.8~N$
and the negative sign means the force between the two charges is attractive, because the two charges have opposite sign.

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3 years ago