Answer:
Explanation:
Mean temperature is given by
Tmean = (Ti + T∞)/2
Tmean = 107.5⁰C
Tmean = 107.5 + 273 = 380.5K
Properties of air at mean temperature
v = 24.2689 × 10⁻⁶m²/s
α = 35.024 × 10⁻⁶m²/s
= 221.6 × 10⁻⁷N.s/m²
= 0.0323 W/m.K
Cp = 1012 J/kg.K
Pr = v/α = 24.2689 × 10⁻⁶/35.024 × 10⁻⁶
= 0.693
Reynold's number, Re
Pv = 4m/πD²
where Re = (Pv * D)/
Substituting for Pv
Re = 4m/(πD)
= (4 x 0.003)/( π × 6 ×10⁻³ × 221.6 × 10⁻⁷)
= 28728.3
Since Re > 2000, the flow is turbulent
For turbulent flows, Use
Dittus - Doeltr correlation with n = 0.03
Nu = 0.023Re⁰⁸Pr⁰³ = (h₁D)/k
(h₁ × 0.006)/0.0323 = 0.023(28728.3)⁰⁸(0.693)⁰³
(h₁ × 0.006)/0.0323 = 75.962
h₁ = (75.962 × 0.0323)/0.006
h₁ = 408.93 W/m².K
Answer:
<em>The Myelinated axons-fibers that are placed in an insulating myelin shealth. </em>
<em>In myelinated axons, charges interchange through the membrane that happens to move between nodes By knowing how quickly the wall (membrane and sheath) of axon part between these bulge tins be electrically charged and discharged by changes in membrane potential at one node, we estimate the haste of tendon impulses along the axon.
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Explanation:
<em>The axons use an active direction 1 um (10 m) Myelinated courage axon Insulating myelin cover 10 um (10m) conducts axoplasm 1 mm node differentiation Evenly spaced bulge of Ranvier of levy transfer across the membrana to create an action potential that continually amplifies and replenishes clectrical signals traveling along the axons</em>
Answer:
What are some types of analysis that an engineer could use to test a design? (Possible answers may relate to: mathematical calculations; testing of stress, loads or function; or computer-aided analysis.)
<em>hope </em><em>it </em><em>helps </em><em>you.</em><em>.</em><em>✌️</em>
Answer:
current is measured in Ampere (A)
In this article, the authors talk about the importance of cybersecurity. Cybersecurity refers to the practice of protecting systems, networks and programs from digital attacks. The authors propose several ways in which we can approach cybersecurity. However, the one that they recommend the most is that of end user education.
End user education refers to the practice of informing your users of the dangers of the internet. This can take place at an individual level or at a corporate level. I do believe that the best way to prevent a cyber attack is through end user education. This is because users are the first line of defense in this situation. They are the ones who are usually contacted, as well as those who can best protect your system against problems.