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Sophie [7]
3 years ago
9

An observer on Earth sees spaceship 1 fly by at 0.80c. 6.0 years later, the observer on Earth sees spaceship 2 fly by at 0.80c,

traveling in the same direction as the first. Both spaceships continue to travel with constant velocities. An observer in spaceship 1 observes Earth to pass spaceship 2 ____ years after Earth passed spaceship 1.
Physics
1 answer:
Lemur [1.5K]3 years ago
5 0

Answer:

t_2=10

Explanation:

From the question we are told that:

Velocity of both spaceships V=0.8c

Time t_1=6

Generally the equation for time of spaceship 2 through earth is mathematically given by

t_2=\frac{t_1}{\sqrt{1-v^2}}

t_2=\frac{6}{\sqrt{1-0.8^2}}

t_2=10

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A space vehicle of mass m has a speed v. At some instant, it separates into two pieces, each of mass 0.5m. One of the pieces is
Damm [24]

Answer:

W = ½ m v²

Explanation:

In this exercise we must solve it in parts, in a first part we use the conservation of the moment to find the speed after the separation

We define the system formed by the two parts of the rocket, therefore the forces during internal separation and the moment are conserved

initial instant. before separation

        p₀ = m v

final attempt. after separation

       p_{f} = m /2  0 + m /2 v_{f}

       p₀ = p_{f}

       m v = m /2 v_{f}

       v_{f}= 2 v

this is the speed of the second part of the ship

now we can use the relation of work and energy, which establishes that the work is initial to the variation of the kinetic energy of the body

     

initial energy

         K₀ = ½ m v²

final energy

        K_{f} = ½ m/2  0 + ½ m/2 v_{f}²

        K_{f} = ¼ m (2v)²

        K_{f} = m v²

         

the expression for work is

         W = ΔK = K_{f} - K₀

         W = m v² - ½ m v²

         W = ½ m v²

5 0
3 years ago
A force acts on a 5kg object at rest. How fast will the object accelerate on a frictionless surface?
MakcuM [25]

Answer: The answer is C.) 25 m/s^2.

Explanation: If you input 5 as s, you would have to use the exponent 2.  This means that you have to multiply 5 by 5.  5 x 5= 25.  

Edit: Also, because the surface is frictionless, it will make the object go faster too.  Nothing can really slow it down unless something blocks it.

8 0
3 years ago
Two positive charges are fixed a distance apart.the sun of their charges is Qt.what charge must each have in order to maximise t
romanna [79]

Answer:

Both charges must have the same charge, Qt/2.

Explanation:

Let the two charges have charge Q1 and Q2, respectively.

Use Coulombs's Law to find an expression for the force between the two charges.

F = k_e\frac{Q_1Q_2}{r^2}, where

Ke is Coulomb's contant and

r is the distance between the charges.

We know from the question that

Q1 + Q2 = Qt

So,

Q2 = Qt - Q1

F = k_e\frac{Q_1(Q_t - Q_1)}{r^2}

Simplify to obtain,

F = \frac{k_e}{r^2} (Q_tQ_1 - Q_1^2)

In order to find the value of Q1 for which F is the maximum, we will use the optimization technique of calculus.

Differentiate F with respect to Q1,

\frac{dF}{dQ_1}  = \frac{k_e}{r^2} (Q_t - 2Q_1)

Equate the differential to 0, to obtain the value of Q1 for which F is the maximum.

\frac{k_e}{r^2} (Q_t - 2Q_1) = 0\\Q_t - 2Q_1 = 0\\2Q_1 = Q_t\\Q1 = \frac{Q_t}{2}

It follows that

Q_2 = \frac{Q_t}{2}.

6 0
3 years ago
6. When sodium and oxygen react to form an ionic compound, the mass of the compound ____ the sum of the masses of the individual
arsen [322]
Because there’s no elemental degradation, the mass of the compound EQUALS the sum of the masses.
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Green plants give us oxygen to breathe using photosynthesis. Here is the unbalanced chemical reaction that occurs:
bekas [8.4K]

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Books are always useful . Give me a "<em>thank</em><em> </em><em>you</em><em>"</em><em> </em>if i've been helpful

4 0
3 years ago
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