Answer: 5 units
Let's begin by stating clear that movement is the change of position of a body at a certain time. So, during this movement, the body will have a trajectory and a displacement, being both different:
The trajectory is the path followed by the body (is a scalar magnitude).
The <u>displacement</u> is the distance in a straight line between the initial and final position (is a vector magnitude).
According to this, in the description of the object (figure attached) placed at 0 on a number line and moving some units to the left and some oter units to the right, we are talking about the path followed by the object, hence its trajectory. So, 13 units is its trajectory.
But, if we talk about displacement, we have to draw a straight line between the initial position of the object (point 0) to its final position (point 5).
Now, being this an unidimensional problem, the displacement vector for this object is 5 units.
Answer:
300 m
Explanation:
The train accelerate from the rest so u = 0 m/sec
Final speed that is v = 80 m/sec
Time t = 30 sec
The distance traveled by first plane = 1200 m
We know the equation of motion where s is distance a is acceleration and u is initial velocity
Using this equation for first plane
As the acceleration is same for both the plane so a for second plane will be 2.67
The another equation of motion is using this equation for second plane
s = 300 m
Answer:
a = 3.61[m/s^2]
Explanation:
To find this acceleration we must remember newton's second law which tells us that the total sum of forces is equal to the product of mass by acceleration.
In this case we have:
Answer:
Explanation:
We have to use the centripetal force equation
we need the radious so we have to isolate "r" and we get
replacing m=65 kg, v= 4.1 m/s and Fc=455N we get
The radius of the amusement park chamber is 2.4m