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2 years ago

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A residential subdivision encompasses 1100 acres with a housing density of four houses per acre. Assume that a high-value reside

nce uses 800 g/day/house and has a fire flow requirement of 1000 gpm. If the water system has a daily peaking factor = 1.64 and an hourly peaking factor = 2.5, determine (a) the average daily demand of this subdivision and (b) the design-demand used to design the distribution system.

1 answer:

aleksandrvk [35]2 years ago

8 0

Answer:

(a). The average daily demand of this subdivision is 2444.44 gallon/min.

(b). The design-demand used to design the distribution system is 2444.44 gallon/min.

Explanation:

Given that,

Area = 1100 acres

Number of house in 1 acres = 4

$\text{Number of house in 1100 acres} = 4\times1100$

$\text{Number of house in 1100 acres} = 4400$

Per house water demand = 800 g/day/house

(a). We need to calculate the average daily demand of this subdivision

Using formula for average daily demand

$\text{average daily demand}=house\times\text{Per house water demand}$

$\text{average daily demand}=4400\times800\ gallon/day$

$\text{average daily demand}=3520000\ gallon/day$

$\text{average daily demand}=\dfrac{3520000}{24\times60}\ gallon/min$

$\text{average daily demand}=2444.44\ gallon/min$

The average daily demand of this subdivision is 2444.44 gallon/min.

(b). We need to calculate the design-demand used to design the distribution system

Using formula for the design-demand

$\text{design demand}=(Q_{max})daily\times\text{fire flow}$

$\text{design demand}=1.64\times2444.4\times1000$

$\text{design demand}=4008816\ gallon/m$

Hence, (a). The average daily demand of this subdivision is 2444.44 gallon/min.

(b). The design-demand used to design the distribution system is 2444.44 gallon/min.

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