Answer:
An increase in air temperature because of its compression.
Explanation:
The Gay-Lussac's Law states that a gas pressure is directly proportional to its temperature in an enclosed system to constant volume.
<em>where P: is the gas pressure, T: is the gas temperature and k: is a constant.</em>
Therefore, due to Gay-Lussac's Law, when the plunger is pushed down very rapidly, the pressure of the air increase, which leads to its temperature increase. That is why cotton flashes and burns.
I hope it helps you!
Answer:
-4*10⁴ units.
Explanation:
As the metal rod was initially neutral (which means that it has the same quantity of positive and negative charges), after being close to the charged sphere, as charge must be conserved, the total charge of the metal rod must still remain to be zero.
So, if due to the influence of the negative charge in the sphere, the half of the road closer to the sphere has a surplus charge of +4*10⁴ units, the charge on the half of the rod farther from the sphere must be the same in magnitude but of the opposite sign, i.e., -4*10⁴ units.
Answer:
The charge resides on the outer surface =
C
Explanation:
Surface area of cell 
Separation between two plate
Dielectric constant 
Potential difference 
The capacitance of parallel plate capacitor in free space is given by,

Where
permittivity of free space = 
The Capacitance of capacitor is increase by
times when it placed in dielectric medium.

And we know that, 
So charge on the outer surface is given by,



Answer:
The horizontal distance the pumpkin will travel after it slips from the eagle is 17.02 m
Explanation:
Given;
height above the ground, h = 16.4 m
speed of the eagle, v = 9.3 m/s
The time it will take the pumpkin to fall at the given height is calculated as;

The horizontal distance traveled at this time is given by;
x = vt
x = (9.3)(1.83)
x = 17.02 m
Therefore, the horizontal distance the pumpkin will travel after it slips from the eagle is 17.02 m
Assuming the ball follows classical 2D projectile motion (moves in a parabola) and that the height y = the maximum height the ball goes in the y direction (because this would be its midpoint), then the velocity at height y is equal to the initial x component of velocity. At the midpoint, the y component is zero, so the velocity only depends on the x component. Projectiles move at constant speed in the x direction, so X = Xo. As long as you know actual values for Vi and either the initial angle or one initial component, then you can solve for Xo using trigonometry. Xo is thus the velocity of the ball once it has reached its maximum height.