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Serga [27]
2 years ago
14

While playing soccer, Caria slides across one of the lines on the field. When she stands up, what base does she stop?

Chemistry
2 answers:
SVEN [57.7K]2 years ago
8 0

Answer:

Canxi hydroxit

Explanation:

sesenic [268]2 years ago
6 0

Answer:

A- calcium hydroxide

Explanation:

Got it right on Edge.

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What volume of hydrogen (in L) is produced
scZoUnD [109]

Answer:

5.26

Explanation:

5 0
3 years ago
My question is what is a cell?
frez [133]

The smallest functional and structural unit of an organism, usually microscopic and consisting of cytoplasm and a nucleus in a membrane.

5 0
3 years ago
The chemical compound, "AB" has a molar mass of 74.548 g/mol.
sladkih [1.3K]

Answer:

47.55%

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4 0
2 years ago
A beaker containing 6.32 moles of PBr3, contains___
NISA [10]

Answer:

3.8 x 10²⁴molecules

Explanation:

Given parameters:

Number of moles  = 6.32moles

Unknown:

Number of molecules  = ?

Solution:

The number of moles can be used to derive the number of molecules found within a substance.

Now,

       1 mole of substance contains 6.02 x 10²³ molecules

     6.32 mole of PBr₃ will contain 6.32 x 6.02 x 10²³ = 3.8 x 10²⁴molecules

8 0
3 years ago
It is desired to produce 2.25 grams of dichloromethane (CH2Cl2) by the following reaction. If the percent yield of dichlorometha
Allushta [10]

Answer:- 3.12 g carbon tetrachloride are needed.

Solution:- The balanced equation is:

CH_4+CCl_4\rightarrow 2CH_2Cl_2

From given actual yield and percent yield we will calculate the theoretical yield that would be further used to calculate the grams of carbon tetrachloride.

percent yield formula is:

percent yield = (\frac{actual}{theoretical})100

65.5=(\frac{2.25}{theoretical})100

theoretical=(\frac{2.25(100)}{65.5})

theoretical = 3.44 g

From balanced equation, there is 2:1 mol ratio between dichloethane and carbon tetrachloride.

Molar mass of dichloroethane is 84.93 gram per mol and molar mass of carbon tetrachloride is 153.82 gram per mol.

3.44gCH_2Cl_2(\frac{1molCH_2Cl_2}{84.93gCH_2Cl_2})(\frac{1molCCl_4}{2molCH_2Cl_2})(\frac{153.82gCCl_4}{1molCCl_4})

= 3.12gCCl_4

So, 3.12 grams of carbon tetrachloride are needed to be reacted.

8 0
3 years ago
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