Limiting reactant : O₂
Mass of N₂O₄ produced = 95.83 g
<h3>Further explanation</h3>
Given
50g nitrous oxide
50g oxygen
Reaction
2N20 + 302 - 2N204
Required
Limiting reactant
mass of N204 produced
Solution
mol N₂O :
mol O₂ :
2N₂O+3O₂⇒ 2N₂O₄
ICE method
1.136 1.5625
1.0416 1.5625 1.0416
0.0944 0 1.0416
Limiting reactant : Oxygen-O₂
Mass N₂O₄(MW=92 g/mol) :
Answer:
onverted
Conversion factor: 946.352946
1) mL = Quart * 946.352946
2) mL = 4.8 * 946.352946
3) mL = 4542.4941
I guess it is the second one but you missed the state symbols.
Glacial till, hope this helps!
Answer:
<h2>14.71 g/cm³</h2>
Explanation:
The density of a substance can be found by using the formula
volume = final volume of water - initial volume of water
volume = 36.5 - 31.4 = 5.1 mL
But
1 mL = 1 cm³
5.1 mL = 5.1 cm³
From the question we have
We have the final answer as
<h3>14.71 g/cm³</h3>
Hope this helps you
