Question

How many solutions does the quadratic have? 2x^2+3x-5​

Answer 1

Answer:

2 solutions

Step-by-step explanation:

Given

2x² + 3x - 5 ( to solve the quadratic equate it to zero )

2x² + 3x - 5 = 0 ← in standard form

(2x + 5)(x - 1) = 0 ← in factored form

Equate each factor to zero and solve for x

2x + 5 = 0 ⇒ 2x = - 5 ⇒ x = - $\frac{5}{2}$

x - 1 = 0 ⇒ x = 1

The 2 solutions are x = - $\frac{5}{2}$ , x = 1