Question

Water with a volume flow rate of 0.001 m3/s, flows inside a horizontal pipe with diameter of 1.2 m. If the pipe length is 10m and we assume fully developed internal flow, find the pressure drop across this pipe length.

Answer 1

Answer:

$\triangle P=1.95*10^{-4}$

Explanation:

Mass $m=0.001$

Diameter $d=1.2m$

Length $l=10m$

Generally the equation for Volume flow rate is mathematically given by

 $Q=AV$

 $V=\frac{Q}{\pi/4D^2}$

 $V=\frac{0.001}{\pi/4(1.2)^2}$

 $V=8.84*10^{-4}$

Generally the equation for Friction factor is mathematically given by

 $F=\frac{64}{Re}$

Where Re

Re=Reynolds Number

 $Re=\frac{pVD}{\mu}$

 $Re=\frac{1000*8.84*10^{-4}*1.2}{1.002*10^{-3}}$

 $Re=1040$

Therefore

 $F=\frac{64}{Re}$

 $F=\frac{64}{1040}$

 $F=0.06$

Generally the equation for Friction factor is mathematically given by

 $Head loss=\frac{fLv^2}{2dg}$

 $H=\frac{0.06*10*(8.9*10^-4)^2}{2*1.2*9.81}$

 $H=19.9*10^{-9}$

Where

$H=\frac{\triangle P}{\rho g}$

$\triangle P=\frac{19.9*10^{-9}}{10^3*(9.81)}$

$\triangle P=H*\rho g$

$\triangle P=1.95*10^{-4}$