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MrRa [10]
3 years ago
15

What would be the average speed of a runner who finished a 400 meter race in 50 seconds?​

Physics
1 answer:
Rom4ik [11]3 years ago
8 0

Answer:800

Explanation:about

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A first-order reaction has a rate constant of 0.241/min. if the initial concentration of a is 0.859 m, what is the concentration
nordsb [41]

Answer: 0.077 M

Explanation:

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant = 0.241minute^{-1}

t = time taken for decay process = 10 minutes

a = initial amount of the reactant= 0.859 M

a - x = amount left after decay process =?

Putting values in above equation, we get:

0.241 minutes^{-1}=\frac{2.303}{10.0}\log\frac{0.859}{a-x}

(a-x)=0.077M

Thus the concentration of a after 10.0 minutes is 0.077 M.


5 0
3 years ago
Read 2 more answers
A group of scientists have obtained some experimental results.
topjm [15]
<span>In order best to find out whether the obtained experimental results are worth mor etime and resources the group of scientists should present their results (could be done also in poster session) to other scientists in order to hear their opinion and get a feedback. The shoudl also ask another researchers to redo the experiments and to compare the results. </span>
4 0
3 years ago
Read 2 more answers
5. What is the frequency of a sound wave when the speed of the sound is 340 m/s and has a wavelength of 1.21 m?​
LekaFEV [45]

Explanation:

v = f × /\

340 = 1.21f

f = 280.99Hz

3 0
3 years ago
What are three (3) things you can do before exercise or sports that will keep you safe?
zaharov [31]

Answer: Drink water, practice, do some light stretches

Explanation:

3 0
3 years ago
A coaxial cable consists of a solid inner cylindrical conductor of radius 2 mm and an outer cylindrical shell of inner radius 3
4vir4ik [10]

Answer:

d) 1.2 mT

Explanation:

Here we want to find the magnitude of the magnetic field at a distance of 2.5 mm from the axis of the coaxial cable.

First of all, we observe that:

- The internal cylindrical conductor of radius 2 mm can be treated as a conductive wire placed at the axis of the cable, since here we are analyzing the field outside the radius of the conductor. The current flowing in this conductor is

I = 15 A

- The external conductor, of radius between 3 mm and 3.5 mm, does not contribute to the field at r = 2.5 mm, since 2.5 mm is situated before the inner shell of the conductor (at 3 mm).

Therefore, the net magnetic field is just given by the internal conductor. The magnetic field produced by a wire is given by

B=\frac{\mu_0 I}{2\pi r}

where

\mu_0 is the vacuum permeability

I = 15 A is the current in the conductor

r = 2.5 mm = 0.0025 m is the distance from the axis at which we want to calculate the field

Substituting, we find:

B=\frac{(4\pi\cdot 10^{-7})(15)}{2\pi(0.0025)}=1.2\cdot 10^{-3}T = 1.2 mT

8 0
3 years ago
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