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Anvisha [2.4K]
3 years ago
12

A force of 15N is action on an area with pressure of 10pa. What is the area covered?

Physics
1 answer:
zloy xaker [14]3 years ago
6 0

Answer:

150

Explanation:

P=F/A

10=15/A

10*15=15/A*15

150=A

I HOPE I HELPED

PLZ MARK ME AS BRAINIEST AND GIVE IT A THANKS

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10. Heat is the transfer of thermal energy from one object to another because of a difference in
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Answer:

Temperature

Explanation:

Heat only flows from one point to the other due to the difference in temperature.

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3 years ago
) each plate of a parallel-plate air-filled capacitor has an area of 0.0020 , and the separation of the plates is an electric fi
Dvinal [7]
I attached the full question.
We know that for a parallel-plate capacitor the surface charge density is given by the following formula:
\sigma=\varepsilon_0 \frac{V}{d}
Where V is the voltage between the plates and d is separation.
Voltage is by definition:
V=Ed
Voltage is analog to the mechanical work done by the force.
Above formula is correct only If the field is constant, and we can assume that it is since no function has been given.
The charge density would then be:
\sigma=\varepsilon_0 \frac{Ed}{d}=\varepsilon_0E\\
\sigma= 8.85\cdot10^{-12}\cdot 2.1\cdot 10^6= 0.0000185\frac{c}{m^2}
Please note that elecric permittivity of air is very close to  elecric permittivity of vacum, it is common to use them <span>interchangeably</span>.

6 0
4 years ago
I need help with part D
natka813 [3]
1).  The little projectile is affected by friction all the way through the block.
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8 0
3 years ago
if a man has a mass of 83 kilograms on earth, what will the force of gravity on his body be on the moon
AnnZ [28]

If a man has a mass of 83 kilograms on Earth, the force of gravity on his body be on the moon 135.6N. force =mass*acc , 83 * 9.8/6= 813.4/6 = 135.6N

3 0
3 years ago
Read 2 more answers
A parallel-plate capacitor with circular plates of radius R is being charged by a battery, which provides a constant current. At
NikAS [45]

To solve this problem it is necessary to apply the concepts related to the magnetic field.

According to the information, the magnetic field INSIDE the plates is,

B=\frac{1}{2} \mu \epsilon_0 r

Where,

\mu =Permeability constant

\epsilon_0 =Electromotive force

r = Radius

From this deduction we can verify that the distance is proportional to the field

B \propto r

Then the distance relationship would be given by

\frac{r}{R} = \frac{B}{B_{max}}

r =\frac{B}{B_{max}} R

r = \frac{0.5B_{max}}{B_{max}}R

r = 0.5R

On the outside, however, it is defined by

B = \frac{\mu_0 i_d}{2\pi r}

Here the magnetic field is inversely proportional to the distance, that is

B \not\propto r

Then,

\frac{r}{R} = \frac{B_{max}{B}}

r = \frac{B_{max}{B}}R

r = \frac{B_{max}{0.5B_{max}}}R

r = 2R

7 0
3 years ago
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