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vladimir1956 [14]

3 years ago

6

How could the location of tests affect the performance of a catapult ?

2 answers:

Svetach [21]3 years ago

6 0

The location of tests affect the performance of a catapult depending on the length of the arm.

<u>Explanation:</u>

A ball from a catapult, will travel a longer distance by increasing the length of the arm. Using the catapult, if the arm is extended to different lengths the wooden ball how far it is thrown can be observed.

This shows that extending the arm length does increase the distance thrown. To shoot a far distance (example for sideways) you need to the pebble sideways and up. By doing this, it can travel a longer distance

Luba_88 [7]3 years ago

3 0

Answer:

It could affect how far the projectile travels

Explanation:

Facing Uphill: Moves less far

Downhill: Moves further

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2.) A fluid moves in a steady manner between two sections in a flow

Talja [164]

Answer:

$250\ \text{lbm/min}$

$625\ \text{ft/min}$

Explanation:

$A_1$ = Area of section 1 = $10\ \text{ft}^2$

$V_1$ = Velocity of water at section 1 = 100 ft/min

$v_1$ = Specific volume at section 1 = $4\ \text{ft}^3/\text{lbm}$

$\rho$ = Density of fluid = $0.2\ \text{lb/ft}^3$

$A_2$ = Area of section 2 = $2\ \text{ft}^2$

Mass flow rate is given by

$m=\rho A_1V_1=\dfrac{A_1V_1}{v_1}\\\Rightarrow m=\dfrac{10\times 100}{4}\\\Rightarrow m=250\ \text{lbm/min}$

The mass flow rate through the pipe is $250\ \text{lbm/min}$

As the mass flowing through the pipe is conserved we know that the mass flow rate at section 2 will be the same as section 1

$m=\rho A_2V_2\\\Rightarrow V_2=\dfrac{m}{\rho A_2}\\\Rightarrow V_2=\dfrac{250}{0.2\times 2}\\\Rightarrow V_2=625\ \text{ft/min}$

The speed at section 2 is $625\ \text{ft/min}$ .

3 0

3 years ago

The cube measures 3.0-ft on all sides and has a density of 3.1 slugs/ft3. How much does it weigh?

kodGreya [7K]

Answer:

W = 2695.14 lb

Explanation:

given,

side of cube = 3 ft

density of the cube = 3.1 slugs/ft³

we know,

$density = \dfrac{mass}{volume}$

mass = density x volume

volume = 3³ = 27 ft³

mass = 3.1 x 27

m = 83.7 slugs.

weight calculation

converting mass from slug to pound

weight of 1 slug is equal to 32.2 lb

now,

weight of the cube is equal to

W = 83.7 slugs x 32.2 lb/slug

W = 2695.14 lb

hence, weight is equal to W = 2695.14 lb

4 0

3 years ago

Express 2/16 in thirty-seconds

mafiozo [28]

Answer:

$\frac{2}{16}$ = $\frac{4}{32}$ in thirty seconds.

Explanation:

one thirty second is one part out of 32 equal section . It is used to describe amounts accurately.

$\frac{2}{16}$ can be easily expressed as $\frac{4}{32}$

3 0

3 years ago

I really need help ASAP!!!

ValentinkaMS [17]

Explanation:

He would work on the thing like in the method you work on your question.

8 0

3 years ago

List 6 different mechanisms in the Rube Goldberg cartoon and predict the purpose of each. Does the mechanism change speed, force

vodka [1.7K]

Answer: Rotary - because it has to

Around in a circle

Explanation:

i hope this helped u

7 0

3 years ago