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vladimir1956 [14]
3 years ago
6

How could the location of tests affect the performance of a catapult ?

Engineering
2 answers:
Svetach [21]3 years ago
6 0

The location of tests affect the performance of a catapult depending on the length of the arm.

<u>Explanation:</u>

A ball from a catapult, will travel a longer distance by increasing the length of the arm. Using the catapult, if the arm is extended to different lengths the wooden ball how far it is thrown can be observed.

This shows that extending the arm length does increase the distance thrown. To shoot a far distance (example for sideways) you need to the pebble sideways and up. By doing this, it can travel a longer distance

Luba_88 [7]3 years ago
3 0

Answer:

It could affect how far the projectile travels

Explanation:

Facing Uphill: Moves less far

Downhill: Moves further

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What gadgets are charge coupled devices used in?
Alinara [238K]

Answer:

They are used in imaging application gadgets such as video cameras,TV, surveillance cameras and document scanners

Explanation:

A charge couple device (CCDs) are highly capable in imagery detector.Its common application is in video and digital imaging.The quality of a charge couple device is determined by factors such as the dynamic range, dark charge level and the quantum efficiency.These devices serve the purpose of detecting optical images though some are installed with applications for data storage.

5 0
2 years ago
What is the area enclosed by the cycle area of the Carnot cycle illustrating on a P-V diagram?
Inga [223]

Answer:

The work of the cycle.

Explanation:

The area enclosed by the cycle of the Pressure-Volume diagram of a Carnot engine represents the net work performed by the cycle.

The expansions yield work, and this is represented by the area under the curve all the way to the p=0 line. But the compressions consume work (or add negative work) and this is substracted fro the total work. Therefore the areas under the compressions are eliminated and you are left with only the enclosed area.

7 0
3 years ago
Damien wants to study the effect on materials let 60 after it is submerged in water for varying durations what type of graphical
Crank

Answer:

please help you are not the intended recipient

7 0
3 years ago
The average age of engineering students at graduation is a little over 23 years. This means that the working career of most engi
RideAnS [48]

Answer:

$916

Explanation:

To solve this, we use the formula

FV = P/i * [(1+i)^n - 1], where

FV = future value of the all the money invested, $5 million

n = time span, = 500 months

P = payment per month

I = interest rate, 9% by 12 months, = 0.0075

Considering that we have been given all in our question, then we substitute directly and solve. So we have,

5000000 = P/0.0075 * [(1+0.0075)^500 -1]

5000000 * 0.0075 = P * [1.0075^500 - 1]

37500 = P * [41.93 - 1]

37500 = P * 40.93

P = 37500/40.93

P = $916.20

Therefore, the engineer needs to save $916 in a month which is the accrued

6 0
3 years ago
A 3-phase induction motor with 4 poles is connected to a voltage source with an amplitude of 209 Vrms and a frequency of 120 Hz.
Ket [755]

Answer:

<em>T = 25.41 Nm</em>

Explanation:

Calculating Nsync (Synchronous Speed):

Nsync = 120f/P

Nsync = 120 x 120 / 4\\Nsync = 3600 rpm

Wsync = 3600 * 2\pi /180\\Wsync = 377 rad/s

Calculating s (Slip):

s = (Nsync - Nm) / Nsync \\[tex]s = (3600-2464)/3600\\s = 0.3156

Calculating Vth (Thevenin Voltage):

Vth = Vph (Xm / \sqrt{Rs^{2} + (Xs+Xm)^{2}  })\\Vth = 209 (76 / \sqrt{(2.3)^{2} + (1.3 + 76)^{2}  }\\Vth = 205.39 V

Calculating Rth (Thevenin Resistance):

Rth = Rs (Xm/Xs + Xm)^{2} \\Rth = 2.3 (76/1.3 + 76)^{2} \\Rth = 2.22 ohm

Calculating Xth (Thevenin Reactance):

Xth = Xs = 1.3 ohm

Calculating Torque:

T = (3Vth^{2}Rr/s) / (Wsync[(Rth+Rr/s)^{2} + (Xth + Xr)^{2}])\\T = (3*205.39*0.7/0.3156) / 377[(2.22+0.7/0.315)^{2} + (1.3+1.8)^{2}]

T = 280699 / 377 [19.69 + 9.61]

<em>T = 25.41 Nm</em>

4 0
3 years ago
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