What is the name of the process taking place in the diagram? Describe the process<br> 1st question

A firm wants to determine the amount of frictional torque in their current line of grindstones, so they can redesign them to be

victus00 [196]

Answer:

a)- 1.799 rad/sec²

b)- 17.6 x 10ˉ³Nm

Explanation:

ω₀ = 720 rev/min x (1 min/60 sec) x (2π rad / 1 rev) = 24π rad/s

a) Assuming a constant angular acceleration, the formula will be

α = (ωf -ω₀) / t

As final state of the grindstone is at rest, so ωf =0

⇒ α = (0-24π) / 41.9 = - 1.799 rad/sec²

b)Moment of inertia I for a disk about its central axis

I = ½mr²

where m=2kg and radius 'r'= 0.099m

I = ½(2)(0.099²)

I = 9.8 x 10ˉ³ kgm²

Next is to determine the frictional torque exerted on the grindstone, that caused it to stop, applying the rotational equivalent of the Newton's 2nd law:

τ = I α =>(9.8 x 10ˉ³)(- 1.799)

τ = - 17.6 x 10ˉ³Nm

(The negative sign indicates that the frictional torque opposes to the rotation of the grindstone).

8 0

3 years ago

What sinle cellular organisms

dusya [7]

<span>A unicellular organism, also known as a single-celled organism, is an organism that consists of only one cell, unlike a multicellular organism that consists of more than one cell.</span>

6 0

3 years ago

is texas near a subduction zone? Justify your answer using the terms plate boundary and plate tectonics

cluponka [151]

Answer:

Subduction is a geological process that takes place at convergent boundaries of tectonic plates where one plate moves under another and is forced to sink due to high gravitational potential energy into the mantle. Regions where this process occurs are known as subduction zones. Rates of subduction are typically measured in centimeters per year, with the average rate of convergence being approximately two to eight centimeters per year along most plate boundaries. so i believe so

Explanation:

nmw

5 0

3 years ago

Professional baseball pitchers deliver pitches that can reach the blazing speed of 100 mph (miles per hour). A local team has dr

maria [59]

Answer: 132.02 J

Explanation:

By definition, the kinetic energy is written as follows:

KE = 1/2 m v²

In our question, we know from the question, the following information:

m = 0.1434 Kg

v= 42.91 m/s

Replacing in the equation for KE, we have:

KE = 1/2 . 0.1434 Kg. (42.91)² m²/s² ⇒ KE = 132.02 N. m = 132.02 J

5 0

3 years ago

A 10.0-cm-long wire is pulled along a U-shaped conducting rail in a perpendicular magnetic field. The total resistance of the wi

Triss [41]

Question:

What are the magnitudes of the pulling force and the magnetic field

Answer:

The magnetic field strength is 2.7 T

The pulling force $F_p$ is 0.975 N

Explanation:

Here we have;

Length of wire, l = 10.0 cm = 0.1 m

Resistance of wire, R = 0.300 Ω

Speed of wire, v = 4.00 m/s

Power dissipated = 3.90 W

Based on the given data, we apply the relation;

$I =\frac{Blv}{R}$ ..............(1)

Where:

B = Magnetic field strength

I = Current

Since P = I²R, we have;

3.9 = I²·0.300Ω

∴ I² = 3.9/0.300 = 13

From which I = √13

Substituting the value of I in equation (1) above, we have;

$\sqrt{13}= \frac{B \times 10.0 \times 4.00}{0.300}$

Therefore;

$B = \frac{\sqrt{13} \times 0.300}{0.1 \times 4.00} = 2.70416 \ T\approx 2.7 \ T$

The magnitude of the pulling force is given by the following relation;

$F_p = F_m = IlB = l\sqrt{\frac{P}{R} } \frac{\sqrt{PR} }{lv} =\frac{P}{v} = \frac{3.9 \ W}{4.00 \ m/s} = 0.975 \ N$

The pulling force $F_p$ = 0.975 N.

8 0

3 years ago

What is the name of the process taking place in the diagram? Describe the process 1st question