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love history [14]
3 years ago
6

Difference between scissors and nut cracker​

Physics
1 answer:
Pavel [41]3 years ago
4 0
But cracked cracks nuts while scripts cut
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As a gas or liquid increases in heat, what direction will it naturally move?
miss Akunina [59]

Hello!

Answer:

When a gas gets hot it should go up because of the pressure.

Explanation:

Hope this helps!

3 0
3 years ago
A sound source A and a reflecting surface B move directly toward each other. Relative to the air, the speed of source A is 28.7
aleksandrvk [35]

(a) 1440.5 Hz

The general formula for the Doppler effect is

f'=(\frac{v+v_r}{v+v_s})f

where

f is the original frequency

f is the apparent frequency

v is the velocity of the wave

v_r is the velocity of the receiver (positive if the receiver is moving towards the source, negative otherwise)

v_s is the velocity of the source (positive if the source is moving away from the receiver, negative otherwise)

Here we have

f = 1110 Hz

v = 334 m/s

In the reflector frame (= on surface B), we have also

v_s = v_A = -28.7 m/s (surface A is the source, which is moving towards the receiver)

v_r = +62.2 m/s (surface B is the receiver, which is moving towards the source)

So, the frequency observed in the reflector frame is

f'=(\frac{334 m/s+62.2 m/s}{334 m/s-28.7 m/s})1110 Hz=1440.5 Hz

(b) 0.232 m

The wavelength of a wave is given by

\lambda=\frac{v}{f}

where

v is the speed of the wave

f is the frequency

In the reflector frame,

f = 1440.5 Hz

So the wavelength is

\lambda=\frac{334 m/s}{1440.5 Hz}=0.232 m

(c) 1481.2 Hz

Again, we can use the same formula

f'=(\frac{v+v_r}{v+v_s})f

In the source frame (= on surface A), we have

v_s = v_B = -62.2 m/s (surface B is now the source, since it reflects the wave, and it is moving towards the receiver)

v_r = +28.7 m/s (surface A is now the receiver, which is moving towards the source)

So, the frequency observed in the source frame is

f'=(\frac{334 m/s+28.7 m/s}{334 m/s-62.2 m/s})1110 Hz=1481.2 Hz

(d) 0.225 m

The wavelength of the wave is given by

\lambda=\frac{v}{f}

where in this case we have

v = 334 m/s

f = 1481.2 Hz is the apparent in the source frame

So the wavelength is

\lambda=\frac{334 m/s}{1481.2 Hz}=0.225 m

8 0
3 years ago
Which of the following is a way earth’s water (hydrosphere) is directly affected by pollution?
ASHA 777 [7]

The toxic runoff from the farms will directly enters the water bodies of the earth through the drainage system.

The emissions from the cars will go into atmosphere and will react with water and then it will enter the earth's water. So, it is not directly affecting the earth's water.

The dumping trash on roadsides do not enter the earth's water. It can enter the earth's water through rains.

The production of oxygen by trees is not pollution.

Hence, option (A) is correct.

6 0
3 years ago
Which element would have the lowest electronegativity? (1 point)O an element with a large number of valence electrons and a larg
nekit [7.7K]

Answer:

an electron with element with large number of valence electron and large atomic <u>radius</u>

8 0
3 years ago
A 30kg bucket of water is lifted vertically 3.0m. How much work was done on the bucket during this movement
Alex

Answer:

Explanation:HELPPPPPPP

3 0
3 years ago
Read 2 more answers
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