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love history [14]
2 years ago
6

Difference between scissors and nut cracker​

Physics
1 answer:
Pavel [41]2 years ago
4 0
But cracked cracks nuts while scripts cut
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On January 22, 1943, the temperature in Spearfish, South Dakota, rose from -4.0∘F∘F to 45.0∘F∘F in just 2 minutes. What was the
Margaret [11]

Answer:

The change in temperature, \Delta T=9.45^{\circ} C

Explanation:

Given that,

The temperature in Spearfish, South Dakota, rose from -4^{\circ} F\ to\ 45^{\circ} F in just 2 minutes. We need to find the temperature change in Celsius degrees. Change in temperature is given by final temperature minus initial temperature such that,

\Delta T=T_f-T_i\\\\\Delta T=45-(-4)\\\\\Delta T=49^{\circ}F

The relation between degrees Celsius and degrees Fahrenheit is given by :

F=1.8C+32

Here, F = 49 degrees

49=1.8C+32\\\\\Delta T=9.45^{\circ} C

So, the change in temperature is 9.45 degree Celsius. Hence, this is the required solution.

8 0
3 years ago
A 9V battery produces a 1.5A current in a piece of wire. What is the resistance of the wire?
MAVERICK [17]

Explanation:

Using Ohm's Law and a bit of substitution, we can use voltage divided by current to solve for resistance. Doing that, we'll get 6 Ohm.

4 0
2 years ago
Define output work and input work​
Olenka [21]

Answer: Input work is the work done on a machine as the input force acts through the input distance.Other ways it would be the work done on a body or system, that is, forces that are applied to the body or system. This is in contrast to output work which is a force that is applied by the body or system to something else.Output work is the work done by a machine as the output force acts through the output distance. The machine does to the object to increase the output distance.

Explanation:

6 0
3 years ago
In Example Suppose the rod stays on the wall in the same position, but the hinge is moved to be at the center of mass position o
navik [9.2K]

Answer:

A

Explanation:

The change in the system’s gravitational potential energy would be zero

4 0
2 years ago
A thin, circular hoop with a radius of 0.22 m is hanging from its rim on a nail. When pulled to the side and released, the hoop
Alex73 [517]

Answer:

Period of oscillation = 1.33 seconds

Explanation:

The period of oscillation is given by:

T = 2π√[I/(MgL)] 

for I = 2MR² and L = R,

Given: L = 0.22m = R

T = 2π√[2R/g] 

T = 2 × 3.142 Sqrt[( 2 × 0.22)/ 9.8]

T = 6.284 Sqrt(0.44/9.8)

T = 6.284 Sqrt(0.0449)

T = 6.284 × 0.2119

T = 1.33 sec

6 0
3 years ago
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