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3 years ago

6

A switch and a fuse should be connected with a live wire in an electric circuit

1 answer:

kykrilka [37]3 years ago

6 0

Answer is A switch or a fuse in an electrical circuit is always connected to the live wire so that the socket or appliance is not live when switched off.

i hope it is helpful

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A spring tide can occur at what day and month?

m_a_m_a [10]

Spring tides occur twice each lunar month all year long (they don't depend on any particular season. When there is a new or full moon the average tidal ranges are larger.

7 0

3 years ago

What voltage can be applied by a resistor<br><br>190 Ω and 100 A?

Anettt [7]

Answer:

V=IR

V=100×190

=19000 V

4 0

3 years ago

A ball is thrown horizontally from the top of a building 54 m high. The ball strikes the ground at a point 35 m horizontally awa

Ivanshal [37]

Answer:

V=34.2 m/s

Explanation:

Given that

Height , h= 54 m

Horizontal distance , x = 35 m

Given that , the ball is thrown horizontally , therefore the initial vertical velocity will be zero.

In vertical direction :

We know that

$V^2_y=U^2_y+2 g h$

Now by putting the values in the above equation we got

$V^2_y=U^2_y+2 g h$

$V^2_y=0^2+2\times 9.81 \times 54$

Assume $g= 9.81 m/s^2$

Thus

$V^2_y=1059.48$

$V_y=\sqrt{1059.48}\ m/s$

$V_y=32.54 m/s$

We also know that

$V_y=U_y+ g\times t$

$32.54=9.81\times t$

$t=\dfrac{32.54}{9.81}=3.31\ s$

In horizontal direction :

$x=U_x\times t$

$U_x=\dfrac{35}{3.31}=10.54\ m/s$

Thus the resultant velocity

$V=\sqrt{V^2_y+U^2_x}$

$V=\sqrt{32.54^2+10.54^2}=34.2\ m/s$

V=34.2 m/s

Therefore the velocity will be 34.2 m/s.

5 0

4 years ago

A proton has a magnetic field due to its spin on its axis. the field is similar to that created by a circular current loop 0.650

Aloiza [94]

Answer:

$\tau=3.48*10^{-26}Nm$

Explanation:

The torque equation is given by:

$\tau=IABsin(\theta)$

Where:

I is the current
A is the area of the loop (A=πR²)
θ is the angle between the normal vector of A and B, in this case it is 90 degrees

So:

$\tau=1.05*10^{4}*\pi *(0.65*10^{-15})^{2}*2.5$

Therefore the torque is:

$\tau=3.48*10^{-26}Nm$

I hope it helps you!

3 0

3 years ago

Read 2 more answers

Arlecino [84]

Answer:

3.844 x 10 to the 5th power

Explanation:

4 0

3 years ago